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Tema [17]
3 years ago
15

. In a group of 37 people waiting in line at the local java house, 18 wanted to order a cappuccino, 20 wanted to

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

36

Step-by-step explanation:

Its 36 because normally someone would do 18+20=38 but you have to remeber in the problem it says 37! so 2 people didn't want anything, minus that and you get 36.

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What is the average of all integers from 11 to 35
horsena [70]
24 becuase add the two together then divide by two
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3 years ago
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2. find the value<br><br><br>pls no links ​
natta225 [31]

Answer:

\displaystyle V = 2144.66 \ ft^3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Volume of a Sphere Formula: \displaystyle V = \frac{4}{3} \pi r^3

  • <em>r</em> is radius

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

<em>r</em> = 8 ft

<u>Step 2: Find Volume</u>

  1. Substitute in variables [Volume of a Sphere Formula]:                                  \displaystyle V = \frac{4}{3} \pi (8 \ ft)^3
  2. Evaluate exponents:                                                                                         \displaystyle V = \frac{4}{3} \pi (512\ ft^3)
  3. Multiply:                                                                                                             \displaystyle V = \frac{2048}{3} \pi \ ft^3
  4. Estimate:                                                                                                           \displaystyle V = 2144.66 \ ft^3
5 0
3 years ago
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3. 1.08<1.6; 1.08 is farther away from the whole number 2, so it is less than 1.6.

6 0
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Joey had 347$ and his friend had 7 times the amount Joey had
Semmy [17]

Answer:

347*7 =2429

Step-by-step explanation:

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How to solve 2.75 + .003+ .158
natita [175]
2.75 + .003 + .158 \\ \\ 2.911 \\ \\ Answer: \fbox {2.911}

This problem can be done using long addition.
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