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qwelly [4]
3 years ago
12

PLEASE HELP ME ASP An ISDN carries a signal in digital form. True False

Computers and Technology
2 answers:
jeyben [28]3 years ago
4 0

Answer:

True. It transmits through digital

AfilCa [17]3 years ago
3 0

Answer:

Its false  I just know it

Explanation:

ISDN eliminates the need for voice digitizers in the central office. It carries the 64Kbps digital signal from the central office directly to the subscriber, and the subscriber can use it for voice or data.

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The scheme function (mult2-diff Ist) should take one argument, a list of numbers, and results in multiplying each number in the
JulijaS [17]

Answer:

The solution code is written in Python.

  1. def mult2_diff(lst):
  2.    num_list = []
  3.    for x in lst:
  4.        num_list.append(x * 2)
  5.    diff = num_list[0]
  6.    for i in range(1, len(num_list)):
  7.        diff = diff - num_list[i]
  8.    
  9.    print(diff)

Explanation:

Firstly, based on the requirement stated in the question, define a function <em>mult2_diff() </em>that takes one argument, <em>lst</em>, which is a list of numbers (Line 1).

This function is expected to multiply each number in the list by two and then followed with computing the difference. To do so, let's try to attempt the first function task, multiplying numbers.  Create a new list, num_list, to hold the multiplied numbers (Line 2). Use a for loop to traverse through each number in the input list, <em>lst</em>, and multiply each of them by two and add it to the <em>num_list </em>(Line 4-5).

To attempt the second function task, create another variable, <em>diff</em>, to hold the value of calculated difference between the numbers in the <em>num_list</em>. Initialize <em>diff </em>with the first number in the <em>num_list</em>. Use a another for-loop to traverse through each number in the num_list starting with second index, <em>1</em>, and calculate the difference between the <em>diff </em>and the current number extracted from the <em>num_list </em>through indexing.

At last print the output of <em>diff</em> (Line 11).

6 0
3 years ago
Write the proghrams for the following:
belka [17]

Answer:

a)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c;

   cin>>a>>b;

   if(a^b)//X-OR operator in C++.

   c=true;

   else

   c=false;

   cout<<c;

return 0;

}

b)

#include <iostream>

using namespace std;

int main() {

   bool a,b,c,d;

   cin>>a>>b>>c;

   if((a^b)^c)//X-OR operator in C++.

   d=true;

   else

   d=false;

   cout<<d;

return 0;

}

Explanation:

The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.

In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.

5 0
3 years ago
Building relationships during your career exploration is called
elena-s [515]
Building relationships during your career exploration is called networking. This is when you are forming relations with those around you so that opportunities may turn up.

Your answer is: Networking 

Have an great day mate!
6 0
4 years ago
Read 2 more answers
Smart art is considered a​
mina [271]

Explanation:

visual representation of information and ideas, and a chart is a visual illustration of numeric values or data. Basically, SmartArt graphics are designed for text and charts are designed for numbers. Use the information below to decide when to use a SmartArt graphic and when to use a chart.

4 0
3 years ago
There are 12 inches in a foot and 3 feet in a yard. Create a class named InchConversion. Its main() method accepts a value in in
Dafna1 [17]

Answer:

import java.util.Scanner;

public class InchConversion

{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

   

 System.out.print("Enter inches: ");

 double inches = input.nextDouble();

 

 inchesToFeet(inches);

 inchesToYards(inches);

}

public static void inchesToFeet(double inches){

    double feet = inches / 12;

    System.out.println(inches + " inches = " + feet + " feet");

}

public static void inchesToYards(double inches){

    double yards = inches / 36;

    System.out.println(inches + " inches = " + yards + " yards");

}

}

Explanation:

In the inchesToFeet() method that takes one parameter, inches:

Convert the inches to feet using the conversion rate, divide inches by 12

Print the feet

In the inchesToYards() method that takes one parameter, inches:

Convert the inches to yards using the conversion rate, divide inches by 36

Print the yards

In the main:

Ask the user to enter the inches

Call the inchesToFeet() and inchesToYards() methods passing the inches as parameter for each method

7 0
3 years ago
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