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3 years ago

What is the interquartile range of this data set 2,5,9,1118,30,42,55,58,73,81

Mathematics

2 answers:

kogti [31]3 years ago

5 0

Answer:

Step-by-step explanation:

If so the inter quartile range = 58 - 9 = 49

andre [41]3 years ago

3 0

Answer:

the answer would be 49 i hope this helps

Step-by-step explanation:

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How do you multiply

arsen [322]

Answer:

example 7 x 3 means you add 7 3 times

Step-by-step explanation:

5 0

3 years ago

The carefully measure out the ingredients to make their pies each pie they make has 5.33 cups of apples in the filling how many

Ivahew [28]

Answer: 31.98 cups

Step-by-step explanation:

if there's 5.33 cups in 1 pie

then there is x cups in 6 pies.

set up a proportion:

5.33 cups = 1 pie

x cups = 6 pies

<em>cross multiplication.</em>

31.98 = x

therefore there are 31.98 cups of apples in 6 pies.

8 0

3 years ago

Read 2 more answers

For Tran thank you appreciate it

Anestetic [448]

Step-by-step explanation:

Let alpha be the unknown angle. We can set up our sine law as follows:

$\frac{ \sin( \alpha ) }{5 \: m} = \frac{ \sin(42) }{3.6 \: m }$

$\sin( \alpha ) = \frac{5 \: m}{3.6 \: m} \times \sin(42) = 0.929$

Solving for alpha,

$\alpha = arcsin(0.929) = 68 \: degrees$

3 0

2 years ago

Evaluate the following

IRINA_888 [86]

(a) $[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

Answer:

$[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5*2.5 }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5}{1} ]^{2}$

*canceling 2.5 in numerator and denominator*

$= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925$

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) $[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3} ] ^{2}$

Answer:

$[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\$

*using $[x^{a}]^b = x^{ab}$ *

$= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}$

*Again, using $[x^{a}]^b = x^{ab}$ *

$= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} } \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1$

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0

3 years ago

PLEASE ANSWER QUICK!!

Dima020 [189]

Answer:

Step-by-step explanation:

7 0

3 years ago