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2 years ago

How is 2/5 + 3/5 = 1

Mathematics

2 answers:

postnew [5]2 years ago

7 0

Answer:

Hey mate......

Step-by-step explanation:

This is ur answer.....

<em>(When you simplify both numbers, you get 1)</em>

Hope it helps!

Brainliest pls!

Follow me! :)

mihalych1998 [28]2 years ago

3 0

Imagine cutting up a pizza into 5 slices

If you take 2 slices, then you take 2 out of the 5, so the fractional amount you took is 2/5 of the full pizza.

If your friend takes 3 slices, then she or he takes 3/5 of the full pizza

Adding the two fractional amounts should get us back to 1 full pizza, which is why 2/5+3/5 = 1.

-----------

We could say this:

2/5 + 3/5 = (2+3)/5 = 5/5 = 1

Dividing any number over itself, as long it's not zero, always leads to 1.

So that's why 5/5 = 1.

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A circular garden has a circumference of

omeli [17]

This solution to this problem is predicated on the fact that the circumference is just: $2\pir$ . A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

$d\pi$

So, solving for both the radius and the diameter gives us:

$d\pi=8xy^2\pi\\ d=8xy^2\\ \\ 2\pi r=8xy^2\pi\\ r=4xy^2$

So, the length of thes traight path that goes through the center of the guardain is just $8xy^2$ , and we can use the radius for the next part of the problem.

The area of a circle is $\pi r^2$ , which means we can just plug in the radius and find our area:

$A=\pi r^2 \implies \\ A=\pi (4xy^2)^2\implies \\ A= 16\pi x^2y^4$

So, we have found our area( $16 \pi x^2 y^4$ ) and the problem is done.

6 0

3 years ago

In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$