You would plot them by month, 170-110= 60 dollar increase. 60 divided by 12 ( for each month) leaves a 5 dollar increase each month. Your coordinates would be 0,110 1,115 2,120 3,125
x would be month
y would be money
Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
This graph is composed of four straight line segments. You'll need to determine the slope, y-intercept and domain for each of them. Look at the first segment, the one on the extreme left. Verify yourself that the slope of this line segment is 1 and that the y-intercept would be 0 if you were to extend this segment all the way to the y-axis. Thus, the rule (formula, equation) for this line segment would be f(x)=1x+0, or just f(x)=x, for (-3,-1). Use a similar approach to write rules for the remaining three line segments.
Present your answer like this:
x, (-3,-1)
f(x) = -1, (-1,0)
one more here
one more here
So to complete the square in
ax^2+bx+c=d form
make sure a=1
subtract c from both sides
take 1/2 of b and square it
add that to both sides
factor perfect square
1x^2-1x-2=0
a=1
move c to other side
add 2 to oth sides
x^2-1x=2
take 1/2 of b and square it
1/2 of -1=-1/2
squaer it
1/4
add that to both sides
x^2-1x+1/4=2+1/4
factor left side
(x-1/2)=2+1/4
first blank is 1/2
2+1/4=8/4+1/4=9/4
blanks are
1/2 and 9/4
-16/-2
Divide numerator & denominator by 2
-8/-1 = 8
