<img src="https://tex.z-dn.net/?f=%283x3%29%2B%283x5%29-%282x-2%29" id="TexFormula1" title="(3x3)+(3x5)-(2x-2)" alt="(3x3)+(3x5)

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anzhelika [568]

3 years ago

-(2x-2)" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

MAVERICK [17]3 years ago

8 0

We can simplify this problem by pairing like terms together.

9x + 15x - 2x + 2
22x + 2

This expression can be simplified down to
22x + 2

tamaranim1 [39]3 years ago

6 0

(3x3)+(3x5)-(2x-2)
9 + 15 -2x-2
24-2x-2
22-2x divide
11

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Construct the confidence interval for the population standard deviation for the given values. Round your answers to one decimal

Alex777 [14]

Answer:

The correct answer is " $2.633< \sigma < 4.480$ ".

Step-by-step explanation:

Given:

n = 21

s = 3.3

c = 0.9

now,

$df = n-1$

$=20$

⇒ $x^2_{\frac{\alpha}{2}, n-1 }$ = $x^2_{\frac{0.9}{2}, 21-1 }$

= $31.410$

⇒ $x^2_{1-\frac{\alpha}{2}, n-1 }$ = $10.851$

hence,

The 90% Confidence interval will be:

= $\sqrt{\frac{(n-1)s^2}{x^2_{\frac{\alpha}{2}, n-1 }} } < \sigma < \sqrt{\frac{(n-1)s^2}{x^2_{1-\frac{\alpha}{2}, n-1 }}$

= $\sqrt{\frac{(21-1)3.3^2}{31.410} } < \sigma < \sqrt{\frac{(21.1)3.3^2}{10.851} }$

= $\sqrt{\frac{20\times 3.3^2}{31.410} } < \sigma < \sqrt{\frac{20\times 3.3^2}{10.851} }$

= $2.633< \sigma < 4.480$

4 0

2 years ago

Please help me with this asap

vagabundo [1.1K]

Answer:

Step-by-step explanation:

3 0

2 years ago

Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-10, 12) and point (5, 3) rounded

Whitepunk [10]

Answer:

<h3>The answer is 17.5 units</h3>

Step-by-step explanation:

Using the distance formula

the distance between (-10, 12) and (5, 3) is

d = 17.492855

We have the final answer as

<h3>d = 17.5 units to the nearest tenth</h3>

Hope this helps you

4 0

3 years ago

Read 2 more answers

Which expression is equivalent to 4×4×4×4?

Lady bird [3.3K]

8*4
I hope that helps !
So, 4*4*4*4 = 16+16 which is 32

4 0

3 years ago

i) Baraka bought ksh.20,000 worth of shares of a company each month. During the first three months, he bought the shares at a pr

Sladkaya [172]

The average price paid by him for the shares after 3 months is ksh. 163.33

<h3>Average</h3>

Total value of shares bought = ksh.20,000

Amount of shares bought in the first three months = ksh.120, ksh.160 and ksh.210

Average price paid for the shares after 3 months

= (120 + 160 + 210) / 3

= 490 / 3

= 163.333333333333

Approximately,

ksh. 163.33

Learn more about average:

brainly.com/question/20118982

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4 0

2 years ago