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3 years ago

What is this simplified? With work? And to the simplest form

Mathematics

1 answer:

mixer [17]3 years ago

8 0

-5 over -4
Which simplifies to 5 over 4

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Matching inequalities with statements

Xelga [282]

Answer:

closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution.

6 0

3 years ago

rusak2 [61]

Answer:

From top to bottom;

1,1,3,3

Step-by-step explanation:

mathematically, for an even function;

f(x) = f(-x)

what this mean is that;

f(-1) = f(1)

f(-3) = f(3)

f(-5) = f(5)

f(-6) = f(6)

so we have it that;

f(-1) = 1

f(-3) = 1

f(-5) = 3

f(-7) = 3

7 0

2 years ago

K & P Toy Store is having a storewide sale. Remote control cars are on sale for 70% of their regular price, and sports equip

lord [1]

Answer:

Answer and steps in picture.

5 0

3 years ago

The total amount, a, in dollars, that Mitra earns is a = 14.6h, where h is the number of hours that she works. What is the const

lesantik [10]

14.6 is the constant because no matter how many hours she will work (that number could change) it will always be a linear growth of 14.6.

7 0

3 years ago

Read 2 more answers

When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w

deff fn [24]

Answer:

A 90% confidence interval for p will be narrower than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - α) % confidence interval for a population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Here $\hat p$ is the sample proportion.

The margin of error of the confidence interval is:

$MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The MOE is dependent on:

Confidence level
Standard deviation
Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of z for 90% confidence level is:

$z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645$

And the critical value of z for 99% confidence level is:

$z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96$

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for p will be narrower than the 99% confidence interval.

6 0

3 years ago