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ira [324]
3 years ago
13

THE Postage rates for sending parcels were $25 for the first 250g and $3.90 for additional 250g or part of 250g. How much did it

cost to send a parcel weighting 830g?
Mathematics
1 answer:
olga_2 [115]3 years ago
8 0
830

830÷250
= 3.32

It's mean that 250 have 3 times...

Frist 250 = $25
Second 250 = $3.90
Third 250 = $3.90

830-3(250)
= 80

So, we have 80g more

80 = $3.90

Total = 25+3.90+3.90+3.90
= $36.70
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What are the steps for x2-11=-2
Rama09 [41]

Answer:

x=3

Step-by-step explanation:

x^2=9

x=3

8 0
2 years ago
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Determine whether the statement is true or false. If it is​ false, rewrite it as a true statement. A population is the collectio
tatuchka [14]

Answer:

False

Step-by-step explanation:

This is false because a population represents all and not some. A population is the collection of all outcomes, responses, measurements, or counts that are of interest. It is not a collection of 'some' outcomes. It is a collection of 'all' outcomes.

A population data set is a set which contains all the items or elements of a specified group or data set. It is a complete list of all the possible data values.

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8 0
3 years ago
A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.
noname [10]

Answer:

Width = 4ft

Height = 4ft

Length = 8ft

Step-by-step explanation:

Given

Volume = 128ft^3

L = 2W

Base\ Cost = \$9/ft^2

Sides\ Cost = \$6/ft^2

Required

The dimension that minimizes the cost

The volume is:

Volume = LWH

This gives:

128 = LWH

Substitute L = 2W

128 = 2W * WH

128 = 2W^2H

Make H the subject

H = \frac{128}{2W^2}

H = \frac{64}{W^2}

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

A = LW + 2(WH + LH)

The cost is:

Cost = 9 * LW + 6 * 2(WH + LH)

Cost = 9 * LW + 12(WH + LH)

Cost = 9 * LW + 12H(W + L)

Substitute: H = \frac{64}{W^2} and L = 2W

Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)

Cost =18W^2 +  \frac{768}{W^2}*3W

Cost =18W^2 +  \frac{2304}{W}

To minimize the cost, we differentiate

C' =2*18W +  -1 * 2304W^{-2}

Then set to 0

2*18W +  -1 * 2304W^{-2} =0

36W - 2304W^{-2} =0

Rewrite as:

36W = 2304W^{-2}

Divide both sides by W

36 = 2304W^{-3}

Rewrite as:

36 = \frac{2304}{W^3}

Solve for W^3

W^3 = \frac{2304}{36}

W^3 = 64

Take cube roots

W = 4

Recall that:

L = 2W

L = 2 * 4

L = 8

H = \frac{64}{W^2}

H = \frac{64}{4^2}

H = \frac{64}{16}

H = 4

Hence, the dimension that minimizes the cost is:

Width = 4ft

Height = 4ft

Length = 8ft

8 0
2 years ago
What is the value of P ? 45/20= 40.5/P?
photoshop1234 [79]

Answer:

P=18

Step-by-step explanation:

45/20= 40.5/P

45p=810

p=18

4 0
2 years ago
In order to prepare for your summer bash, you go to the supermarket to buy hamburgers and
timofeeve [1]

The complete question is:

In order to prepare for your summer bash, you go to the supermarket to buy hamburgers and chicken. Hamburgers cost $2 per pound and chicken costs $3 per pound. You have no more than $30 to spend.  You expect to purchase at least 3 pounds of hamburgers.  

  • Write a system of inequalities to represent this situation.
  • Graph the system of inequalities on the grid.
  • Give three possible combinations for buying hamburgers and chicken for your summer bash.

Justify your answers

Answer:

A) System of inequalities:

  • 2x + 3y ≤ 30
  • x ≥ 3
  • x ≥ 0
  • y ≥ 0

B) Graph: see the picture attached

C) Three possible combinations:

  • 3 pounds of hamburgers and 8 pounds of chicken
  • 3 pounds of hamburgers and 0 pounds of chicken
  • 15 pounds of hamburgers and 0 pounds of chicken

Explanation:

<u>A) Write the system of inequalities to represent this situaction.</u>

<u>1. Variables:</u>

  • x: number of pound of hamburgers
  • y: number of pound of chicken

<u>2. Costs:</u>

  • x pounds of hamburgers at $2 per pound: 2x
  • y: pounds of chicken at $3 per pound: 3y

  • total cost: 2x + 3y

<u>3. First constraint:</u>

  • You have no more than $ 30 to spend: means that the cost of what you buy can be at most (less than or equal to) $ 30.

  • 2x + 3y ≤ 30

<u>4. Second constraint:</u>

  • You expect to purchase at least 3 pounds of hamburgers: means that the number of pounds of hamburgers may be greater than or equal to 3.

  • x ≥ 3

<u>5. Additional constraints:</u>

  • Both, x and y cannot be negative: x, y ≥ 0

<u>6. System of equations:</u>

  • 2x + 3y ≤ 30
  • x ≥ 3
  • x ≥ 0
  • y ≥ 0

<u>B) Graph </u>

You have to graph all the constraints in a x-y coordinate system.

<u>1. To graph 2x + 3y ≤ 30 graph the line 2x + 3y = 30</u>

  • Choose the y-intercept and x-intercept.
  • x = 0 ⇒ 3y = 30 ⇒ y = 10 ⇒ point (0, 10)
  • y = 0 ⇒ 2x =30 ⇒ x = 15 ⇒ point (15, 0)
  • With two points you can draw the line
  • Clear y: y ≤ 10 - 2x/3. Since, the symbol is ≤ you shade the region below the line, and the line is included, so you draw it as as solid line.

<u>2. To graph x ≥ 3 just draw the vertical line x = 3 and shade the region to the right of it. The points of the line are included (solid line).</u>

<u>3. The constraints x ≥ 0 and y ≥ 0 </u>mean that the region is restricted to the first quadrant (including the positive axis).

<u>4. The feasible solutions</u> are the set of points inside the common regions (intersection).

With all that information the graph is the one attached. The feasible solutions is the region defined by the triangle with vertices (3,8), (3,0), and (15,0).

<u>C) Give 3 possible combinations.</u>

You can pick any three points inside the region, as long as the coordinates are integer numbers. For instance the 3 vertices are solutions:

  • (3, 8) ⇒ 3 pounds of hamburgers and 8 pounds of chicken
  • (3,0) ⇒ 3 pounds of hamburgers and 0 pounds of chicken
  • (15,0) ⇒ 15 pounds of hamburgers and 0 pounds of chicken

You could also prove that (5,4), 5 pounds of hamburgers and 4 pounds of chicken meet, the inequalities.

This is how you prove it:

  • 5 ≥ 0
  • 5 ≥ 3
  • 4 ≥ 0
  • 2(5) + 3(4) = 10 + 12 = 22 ≤ 30

And you can do the same for any pairs to verify whether they are solution or not.

7 0
3 years ago
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