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3 years ago

What is this answer?

Mathematics

1 answer:

Bogdan [553]3 years ago

3 0

Shidd I couldn’t tell you but like this

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Luca is 9 years old and 129 cm tall.Medical charts show that a Boy’s height at age 9 is 3/4 of his predicted adult height.Predic

Arlecino [84]

About 172 centimeters tall.

Since he is about 3/4 his average adult height, you simply divide his current height by .75

129/.75 = 172

6 0

3 years ago

Read 2 more answers

Please help quickly for 5 stars and brainliest!!

alexandr402 [8]

1.
Height h = 240 feet
We insert it into formula.
$240 = -16 t^{2} +128t$
Now we solve this for t:
$16 t^{2} -128t +240 = 0 /16 \\ t^{2} - 8t +15 =0 \\ t_{1} = 5 t_{2} = 3$

We have two answers as the rocket will pass this height on it's way up and down.

2.
Height h = 0 feet
We insert it into formula.
$0=-16 t^{2} +76t + 2$
Now we solve this for t:
$16 t^{2} - 76t -2 = 0 /2 \\ 8t^{2} - 38t - 1 = 0 \\ t_{1} = 5 t_{2} = -1$
We do not consider solution -1 as the time can not be negative. Our solution is 5s.

3.
Height at bottom of hill h = 0 feet
We insert it into formula.
$v^{2} = 64 * 0 = 0 ft/s$

7 0

4 years ago

Simplify -14x^3/x^3-5x^4

Katyanochek1 [597]

Answer:

The answer is D

Step-by-step explanation:

7 0

3 years ago

Help me please anyone

ruslelena [56]

Answer:

X=3

Step-by-step explanation:

180-105-46=6x+11

6x+11=29

6x=18

x=3

4 0

3 years ago

Find (a) the arc length and (b) the area of a sector.

Brut [27]

Answer:

a) 23.56 ft (2 dp)

b) 58.90 ft² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{3 \pi}{2}$
r = 5 ft

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 5\left(\dfrac{3 \pi}{2}\right)\\& = \dfrac{15}{2} \pi \\& = 23.56\: \sf ft\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(5^2) \left(\dfrac{3 \pi}{2}\right)\\\\& = \dfrac{25}{2}\left(\dfrac{3 \pi}{2}\right)\\\\ & = \dfrac{75}{4} \pi \\\\& = 58.90 \: \sf ft^2\:(2\:dp)\end{aligned}$

6 0

3 years ago

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