Since Density = mass/ volume (d = m / v), and assuming the 15 fish weigh 1 gram each - if weight of each fish isn't given - (making that a total of 15 grams),
D = m / v
0.3 = 15 / v
v = 15 / 0.3 = 50 ft cubed
Hope this answers your question correctly :)
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Answer:
The second option annually
Step-by-step explanation:
(4,900×12)×10 the multiply by 2.9%. Take that number and add on every 10 years
Step-by-step explanation:
9-(10) = 9-10 = -1
Hope this helps
Try this:
1) note that weight of pure antifreeze before mixing and after mixing is the same. So, if 'x' is weight of pure antifreeze in 50% solution, it is possible to make up equation before mixing: 0.5x+0.2*90.
2) there are 0.2*90=18 gal. of pure antifreeze in the 20% solution. If 'x' gal. is the weight of pure antifreeze in 50% sol. and 18 gal. is the weight of pure antifreeze in 20% sol., it is possible to make up an equation after mixing: 0.4(x+18).
3) using the both parts: 0.5x+0.2*90=0.4(x+18) ⇒ x=54 gal. of <u>pure</u> weight.
4) to find 50% solution of 54 gal. pure weight just 54:0.5=108 gal.
Answer: 108 gal.
