Answer:
.22
twenty two hundredths as a decimal.
Answer:
- see below for a drawing
- the area of one of the trapezoids is 20 units²
Step-by-step explanation:
No direction or other information about the desired parallelogram is given here, so we drew one arbitrarily. Likewise for the segment cutting it in half. It is convenient to have the bases of the trapezoids be the sides of the parallelogram that are 5 units apart.
The area of one trapezoid is ...
A = (1/2)(b1 +b2)h = (1/2)(3+5)·5 = 20 . . . . square units
The sum of the trapezoid base lengths is necessarily the length of the base of the parallelogram, so the area of the trapezoid is necessarily 1/2 the area of the parallelogram. (The area is necessarily half the area of the parallelogram also because the problem has us divide the parallelogram into two identical parts.)
36 miles. Call <span>Fort Collins point F, Cheyenne, point C, and Laramie point L. We know that angle F=46.5 degrees, angle L=43.6 degrees, and FC=3.2 inches. </span>Use the law of sines, sinF/LC=sinL/FC, LC=sin46.5*3.2/sin43.6=2.32/0.69=3.36 inches. Since one inch represents 10.6 miles, 3.36 inches is 36 miles, the distance from L to C.
Answer:
Area of ΔPQR = 25 units
Step-by-step explanation:
We will use the following formula to calculate the area of triangle ΔPQR:
A = 1/2 | x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂) | = 1/2 |(-6(1+3) +2(-3-7) +(-1)((7-1)| =
A = 1/2 |-6 · 4 + 2 · (-10) + (-1) · 6| = 1/2 | -24-20-6| = 1/2 | -50| = 1/2 · 50 = 25
A = 25 units
God with you!!!
Answer:
14 units
Explanation:
If quadrilaterals HGEF and DCAB are similar, then the ratio of some corresponding sides is:

Substitute the given side lengths:

The measurement of line EG is 14 units.