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3 years ago

Find the x component of the vector 92.5 m 32.0 degrees

Mathematics

2 answers:

tigry1 [53]3 years ago

7 0

2960m that’s itabhabahaha

Marrrta [24]3 years ago

5 0

2960m It should be correct

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Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

Please help on this ? :)

Marina86 [1]

Answer: C.The graph of the function starts lows and ends high.

5 0

3 years ago

Read 2 more answers

108,930,000 in scientific notation

Ann [662]

Answer:

the answer is 1.0893×10 it is now in scientific notation

3 0

3 years ago

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Identify the domain and range of each relation. Use a mapping diagram to determine whether the relation a function.

Xelga [282]

Answer:

Domains- 6, 5, 1, 7

Ranges- -7, -8, 4, 5

6 0

3 years ago

What is the area of this composite shape

makvit [3.9K]

Answer:

51in

Step-by-step explanation:

you first have to find the area of the square by multiplying 6 and 7 which is 42. Then you have to find area of the triangle and the formula to do that is (length×width)÷2 . to find the length you have to subtract 7 from 13 which is 6 and the length you have to do 6-3 which is 3 then (6×3)÷2=9 and then you add the area of the square and the area of the triangle and get 42+9=51

6 0

3 years ago