Let's say that h(x) = x+3. To find the inverse switch h(x) and x and call h(x) by its inverse name
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. so f(x) = x - 3.
so h(f(x)) = (x - 3) + 3 = x what we did is plug f(x) in for x which is the inverse of h(x). The answer is h(f(x)) =x.
Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
Answer:
D
21/7 is basically 1/3 so it would be C
Step-by-step explanation:
90
one revolution is the circumference of the circle.
C=
d=90