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3 years ago

I NEED HELP ON DOING THIS

Mathematics

2 answers:

-BARSIC- [3]3 years ago

5 0

1. Write out an equation to solve this.
2x + 7x - 9 = 90 degrees

2. Add 2x to 7x
9x - 9 = 90 degrees

3. Add 9 to both sides of the equal sign
9x = 99 degrees

4. Divide 9x by 9 to get x
x = 11 degrees

stira [4]3 years ago

4 0

If all the angles add up to 90 degrees then you can set the equation 7x-9*2x=90
Simplify
9x-9=90
Plus 9 both sides
9x=99
Divide by 9 on both sides
X=11

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A jet travels 590 miles in 5 hours at this rate how far could the jet fly in 10 hours

Setler [38]

Answer:

1180 miles

Step-by-step explanation:

590 x 2. If 590 miles in 5 hours then in ten it would be double. 590x2=1180.

So 1180 miles

Hope this helps

4 0

2 years ago

(a) A mixed hockey team of 11 must have at least 5 boys and at least 5 girls. There are 7 boys and 8 girls available for selecti

guajiro [1.7K]

Answer:

A) I) 49 teams

II)63 teams

B) 28 teams

Step-by-step explanation:

A) a team of 5 boys and 6 Girls

=7C5+ 8C6

= 21+28

= 49 teams

a team of 6 boys and 5 girls

= 7C6 + 8C5

= 7+56

= 63 teams

B) one girl is kept constant already and a guy has injury

Girls remaining to choose from 7

Boys remaining to choose from 6

= 1 +7C5 + 6C5

= 1+21+6

= 28 teams

5 0

3 years ago

Find the quotient of `(2i(4+5i)(4-5i))/(4+i)`, and express it in the simplest form.

DIA [1.3K]

Answer:

(328i + 82) / 17

Step-by-step explanation:

`(2i(4+5i)(4-5i))/(4+i)

= (2i(16 - 25i^2)) / (4 + i)

= (2i( 16 + 25) )) / (4 + 1) [Note:- i^2 = -1]

= 82i / (4 + i)

= 82i(4 - i) / (4 + i)(4 - 1)

= 328i + 82 / (16 - i^2)

= (328i + 82) / 17

5 0

3 years ago

41% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the

lys-0071 [83]

Answer:

a) 0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly five.

b) 0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least six.

c) 0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have very little confidence in newspapers, or they do not. The answers of each adult are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

41% of U.S. adults have very little confidence in newspapers.

This means that $p = 0.41$

You randomly select 10 U.S. adults.

This means that $n = 10$

(a) exactly five

This is $P(X = 5)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.41)^{5}.(0.59)^{5} = 0.2087$

0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly five.

(b) at least six

This is:

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.41)^{6}.(0.59)^{4} = 0.1209$

$P(X = 7) = C_{10,7}.(0.41)^{7}.(0.59)^{3} = 0.0480$

$P(X = 8) = C_{10,8}.(0.41)^{8}.(0.59)^{2} = 0.0125$

$P(X = 9) = C_{10,9}.(0.41)^{9}.(0.59)^{1} = 0.0019$

$P(X = 10) = C_{10,10}.(0.41)^{10}.(0.59)^{0} = 0.0001$

Then

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.1209 + 0.0480 + 0.0125 + 0.0019 + 0.0001 = 0.1834$

0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least six.

(c) less than four.

This is:

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.41)^{0}.(0.59)^{10} = 0.0051$

$P(X = 1) = C_{10,1}.(0.41)^{1}.(0.59)^{9} = 0.0355$

$P(X = 2) = C_{10,2}.(0.41)^{2}.(0.59)^{8} = 0.1111$

$P(X = 3) = C_{10,3}.(0.41)^{3}.(0.59)^{7} = 0.2058$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0051 + 0.0355 + 0.1111 + 0.2058 = 0.3575$

0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

5 0

3 years ago

Is y=4x proportional or non-proportional

jolli1 [7]

Answer:

No its nonportional

Step-by-step explanation:

proportional relationship doesn't have any operation between the “k” and “x” where K is the unit rate or the constant of proportionality.

4 0

3 years ago

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