Answer:
95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].
Step-by-step explanation:
We are given that 15% of a random sample of 300 U.S. public high school students were obese.
Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;
P.Q. =
~ N(0,1)
where,
= sample % of U.S. public high school students who were obese = 15%
n = sample of U.S. public high school students = 300
p = population percentage of all U.S. public high school students
<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>
<u></u>
<u>So, 95% confidence interval for the population proportion, p is ;</u>
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level
of significance are -1.96 & 1.96}
P(-1.96 <
< 1.96) = 0.95
P(
<
<
) = 0.95
P(
< p <
) = 0.95
<u>95% confidence interval for p</u> = [
,
]
= [
,
]
= [0.110 , 0.190]
Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].
A real number and a rational number
The answer is A.
y is the total cost, than you would need to multiply x, the number additional number of square feet, which is 3.5x. you would then add 95 dollars to the equation to represent the initial fee. So the equation would look like Y=3.5x+95.
- beanz
Subtract 58 from 93, it's 35
Answer:
landed
landed since it has to be past tense.