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antiseptic1488 [7]
3 years ago
8

Find the equation of the linear function h that has h(12)=-7 and that is perpendicular to q(a)=1/2a+38.. I don’t understand how

to get the equation and how to write it into slope intercept form
Mathematics
1 answer:
Effectus [21]3 years ago
7 0

Step-by-step explanation:

q(a) = ½a + 38

The slope of q is ½.  So the perpendicular slope is -1/½ = -2.

Write h(x) in point-slope form:

h − (-7) = -2 (x − 12)

h + 7 = -2 (x − 12)

Simplify to get slope-intercept form.

h + 7 = -2x + 24

h = -2x + 17

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I'll show a step-by-step. I'm not in the mood to explain right now lol.

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---

hope it helps

sorry if it doesn't

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