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antiseptic1488 [7]
3 years ago
8

Find the equation of the linear function h that has h(12)=-7 and that is perpendicular to q(a)=1/2a+38.. I don’t understand how

to get the equation and how to write it into slope intercept form
Mathematics
1 answer:
Effectus [21]3 years ago
7 0

Step-by-step explanation:

q(a) = ½a + 38

The slope of q is ½.  So the perpendicular slope is -1/½ = -2.

Write h(x) in point-slope form:

h − (-7) = -2 (x − 12)

h + 7 = -2 (x − 12)

Simplify to get slope-intercept form.

h + 7 = -2x + 24

h = -2x + 17

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Romashka [77]
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f(1) = (1)^2 - 5 = 1 - 5 = -4
 AVR = \frac{-4+4}{1+1}
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 Answer:
 
these functions from the greatest to the least value based on the average rate of change are:
 f(x) = x^2 + 3x
 
f(x) = 3x - 8
 
f(x) = x^2 - 5
 
f(x) = x^2 - 2x
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