∠ABC is formed by two tangents intersecting outside of a circle. If minor arc AC = 110°, what is the measure of ∠ABC?
2 answers:
Answer:
∠ABC = 70°
Step-by-step explanation:
As shown in the figure attached AB and BC are two tangents drawn on a circle touching at A and C.
Measure of minor arc = 110°
And we have to find the measurement of ∠ABC.
Since measure of minor arc AC = 110°
and m(minor arc AC) + m(major arc AC) = 360°
110° + major arc AC = 360°
major arc AC = 360 - 110 = 250°
and angle formed outside the circle by two tangents formed at B = 1/2(difference of intercepted arcs)
=
Therefore answer is ∠ABC = 70°
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Answer:
a) Area of the base of the pyramid =
b) Area of one lateral face =
c) Lateral Surface Area =
d) Total Surface Area =
Step-by-step explanation:
We are given the following dimensions of the triangular pyramid:
Side of triangular base = 6mm
Height of triangular base = 5.2mm
Base of lateral face (triangular) = 6mm
Height of lateral face (triangular) = 8mm
a) To find Area of base of pyramid:
We know that it is a triangular pyramid and the base is a equilateral triangle.
b) To find area of one lateral surface:
Base = 6mm
Height = 8mm
Using equation (1) to find the area:
c) To find the lateral surface area:
We know that there are 3 lateral surfaces with equal height and equal base.
Hence, their areas will also be same. So,
d) To find total surface area:
Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>
Hence,
a) Area of the base of the pyramid =
b) Area of one lateral face =
c) Lateral Surface Area =
d) Total Surface Area =