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AlexFokin [52]
3 years ago
10

∠ABC is formed by two tangents intersecting outside of a circle. If minor arc AC = 110°, what is the measure of ∠ABC?

Mathematics
2 answers:
tatyana61 [14]3 years ago
6 0
The answer to this problem is 70. Hope I helped :)

Mariulka [41]3 years ago
5 0

Answer:

∠ABC = 70°

Step-by-step explanation:

As shown in the figure attached AB and BC are two tangents drawn on a circle touching at A and C.

Measure of minor arc = 110°

And we have to find the measurement of ∠ABC.

Since measure of minor arc AC = 110°

and m(minor arc AC) + m(major arc AC) = 360°

110° + major arc AC = 360°

major arc AC = 360 - 110 = 250°

and angle formed outside the circle by two tangents formed at B = 1/2(difference of intercepted arcs)

=\frac{1}{2}(major arc - minor arc)=\frac{1}{2}(250-110)=\frac{1}{2}(140)=70

Therefore answer is ∠ABC = 70°

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Assume the average height for American women is 64 inches with a standard deviation of 2 inches. A sorority on campus wonders if
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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume the average height for American women is 64 inches with a standard deviation of 2 inches

This means that \mu = 64, \sigma = 2

A) Calculate the standard error for the distribution of means.

Sample of 25 means that n = 25, so s = \frac{2}{\sqrt{25}} = 0.4.

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Sample mean of 65 means that X = 65.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{0.4}

Z = \frac{65 - 64}{0.4}

Z = 2.5

C) What is the approximate percentile for this sample? Enter as a whole number.

Z = 2.5 has a p-value of 0.9938, so 0.99*100 = 99th percentile.

D) If the sorority actually had 36 members (still with an average of 65 inches), would you expect the percentile value to increase or decrease? why?

The larger sample size would lead to a smaller margin of error, which would lead to a higher z-score and a increased percentile.

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