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nexus9112 [7]
4 years ago
13

The position of the particle moving in space at time t ≥ 0 is r(t) = (2 + 2 cos(t))i − 2 sin(t)j + (3 − t π )k. Find the first t

ime moment t0 such that the velocity vector v(t0) is orthogonal to the vector i − j.
Mathematics
1 answer:
jekas [21]4 years ago
5 0

Answer:

t0 = π/4

Step-by-step explanation:

The velocity v(t) = r'(t) = <-2sint,-2cost>

Since <1,-1>⊥v, <1,-1>•v=0. So,

(1)(-2sint) + (-1)(-2cost) = 0

cost - sint = 0

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Answer:

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Step-by-step explanation:

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When two lines cross like this, sum of measures of opposite angles is 180.
this means that:
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4 years ago
Consider two competing firms in a declining industry that cannot support both firms profitably. Each firm has three possible cho
yaroslaw [1]

Answer:

a) attached below

b)  ( T,T )

c) The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

d) The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 )

Step-by-step explanation:

A) write down the game in matrix form

let: E = exit at the industry immediately

     T = exit at the end of the quarter

     N = exit at the end of the next quarter

matrix is attached below

B) weakly dominated strategies is ( T,T )

C) Find the pure-strategy Nash equilibria

The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

D ) Find the unique mixed-strategy Nash equilibrium

The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 ) since T is weakly dominated then the mixed strategy will be NE

Assume that P is the probability of firm 1 exiting immediately ( E )

and q is the probability of firm 1 staying till next term ( N ) ∴ q = 1 - P.

hence the expected utility of firm 2 choosing E = 0 while the expected utility of choosing N = 4p - 2q .

The expected utilities of E and N to firm 2 =

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Svet_ta [14]

Step-by-step explanation:

Something to keep in mind is that anything greater than 0 is positive and anything less than 0 is negative

a is to the right of 0 and 1 making it a positive number

b is to the left of 0 making is a negative number

A. a is greater than 1 and b is a negative number

negative number * positive number = negative number

We already know that a is greater than 1 so ab has to be much less than -1 making ab+1 a negative expression

B. Looking at the number line, you can tell that the distance between 1 and a is a bit less than the distance between 0 and 1

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Because of this, a-2 is negative

C. -b

b is a negative number which means that -b would be positive

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Since b is already negative, the expression would simplify to two positive numbers being added

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Answer:

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