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nexus9112 [7]
3 years ago
13

The position of the particle moving in space at time t ≥ 0 is r(t) = (2 + 2 cos(t))i − 2 sin(t)j + (3 − t π )k. Find the first t

ime moment t0 such that the velocity vector v(t0) is orthogonal to the vector i − j.
Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer:

t0 = π/4

Step-by-step explanation:

The velocity v(t) = r'(t) = <-2sint,-2cost>

Since <1,-1>⊥v, <1,-1>•v=0. So,

(1)(-2sint) + (-1)(-2cost) = 0

cost - sint = 0

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MrMuchimi

Answer:

There appears to be a difference between the pulse rates from samples of adult males and females. The average pulse rate of males is 63.75 while that of females is 75.875.

Coefficient of Variation (male) = 33.44%

Coefficient of variation (female) = 28.35%

Step-by-step explanation:

Mean (male) = \frac{sum of x}{n} =\frac{1020}{16} =63.75

Mean (female) = \frac{sum of y}{n} = \frac{1214}{16} = 75.875

Standard Deviation (male) = \sqrt{\frac{sum(x-63.75)^2}{16-1} } =21.315

Standard Deviation (female) = \sqrt{\frac{sum(y-75.875)^2}{16-1} } = 21.512

Coefficient of Variation  = \frac{Std dev}{mean} *100

For male, CV = \frac{21.315}{63.75} *100=33.44%%

For female, CV = \frac{21.512}{75.875} *100=28.35%

Comparison : Pulse rates of males has more variability than that of females since it has a greater coefficient of variation.

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Answer:

\huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{:}\

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