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s2008m [1.1K]
2 years ago
7

In a certain city, the monthly cost of residential electric service is given by the function C = 0.08n + 12, where n is the numb

er of kilowatt hours (kWh) used, 8 cents is the cost per kWh, and $12 is a fixed charge. Find the monthly bill if 400 kWh were used. $
Mathematics
1 answer:
Anarel [89]2 years ago
3 0

Answer:

be able to make it to the meeting tonight but I can tomorrow if you have time can you come to my house and I will be there

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¿Can i get the answer?
NikAS [45]

Answer:

15.7

Step-by-step explanation:

5 x 3.14(pi) = 15.7

3 0
2 years ago
Rational numbers with distribute property
Svetradugi [14.3K]

I'm not sure what this means. If you have choices you should list them.

(1/2)*(1/4 + 1/6) is an example of what should be given. There are two ways to solve this.

1. Use the distributive property.

1/2*1/4 + 1/2* 1/6

1/8 + 1/12 Which can be added using the LCD of 24

3/24 + 2/24 = 5/24

Method 2

Add what is inside the brackets first.

1/2 ( 1/4 + 1/6)

1/2(3/12 + 2/12 = 5/12

Now multiply by 1/2

1/2(5/12) = 5*1/(12 * 2) = 5 / 24 Same answer.

4 0
2 years ago
Please help me :( with this
hodyreva [135]

Answer:

21

Step-by-step explanation:

Similar triangles. MNL is just ABC but 3/4 the size.

x = 8*3/4 = 6

perimeter woudl be 6+6+9 = 21

7 0
3 years ago
he coordinate grid shows the graph of four equations: A coordinate grid is shown from negative 12 to positive 12 on the x axis a
denis23 [38]

The set of equation that is known to have 5 and 0 as solutions is A and B.

<h3>How to solve for the system of equations.</h3>

From the graph that we have here in this question, we are supposed to identify the equations that have this point.

We can do this by tracing the lines in order to locate 5 and 0 on the grid.

When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.

Read more on graphs here:

brainly.com/question/10465970

#SPJ1

6 0
2 years ago
1. Consider the figure below where ZV is parallel to WY.
Hatshy [7]

Answer:

Part A:

m∠VHT = 152°

Part B:

m∠QTS = 152°

Part C:

m∠ZHQ = 28°.

Step-by-step explanation:

Part A:

The given parameters are;

m∠HXU = 113°

Segment BQ and segment UD intersect at m∠XAT = 95°

We have that m∠HXU + m∠HXS = 180° (Angles on a straight line)

Therefore;

m∠HXU  = 180° - m∠HXS = 180° - 113° = 67°

m∠HXU = 67°

m∠XAT + m∠XAH = 180° (Angles on a straight line)

m∠XAH  = 180° - m∠XAT = 180° - 95° = 85°

m∠XAH = 85°

In triangle XAH, we have;

m∠XAH + m∠HXU + m∠XHA = 180° (Angle sum property of a triangle)

∴ m∠XHA = 180° - (m∠XAH + m∠HXU) = 180° - (85° + 67°) = 28°

m∠XHA = 28°

m∠VHT + m∠XHA = 180° (Angles on a straight line)

m∠VHT  = 180° - m∠XHA = 180° - 28° = 152°

m∠VHT = 152°

Part B:

m∠QTS ≅ m∠VHT (Corresponding angles are congruent)

∴ m∠QTS = 152° (Substitution property)

Part C:

m∠ZHQ ≅ m∠XHA  (Reflexive property)

∴ m∠ZHQ = 28°.

3 0
3 years ago
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