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Nady [450]
2 years ago
6

John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs

to maintain a ratio of pumpkin to green beans of 5 to 2. If he wants to use a total of 140 cans, how many cans of green beans should he use? A. 38 cans B. 40 cans C. 22 cans D. 7 cans
Mathematics
1 answer:
alukav5142 [94]2 years ago
5 0
This is a part:part ratio. to solve it we need to convert it into a part:whole ratio. we do this by adding the parts. the ratio of pumpkin cans to total cans is 5:7. 140/7=20. 20x5=100. 20x2=40. The answer is B. 40 cans.
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The value of x in the expression<br> 2x/3 - 7 = 5 is
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Answer:

The answer is X = 18

Step-by-step explanation:

2x/3 - 7 = 5

Multiply both sides if the equation by 3 : 2x - 21 = 15

Move the constant to the right hand side and change its sign : 2x = 15 + 21

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Answer X = 18

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Given s(x) = 2x - 3 and t(x) = 5x + 4. Find the formula and domain for v(x) = s (x) / t (x) and w(x) = t (x) / s (x)
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In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
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Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

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So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

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