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Nady [450]
3 years ago
6

John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs

to maintain a ratio of pumpkin to green beans of 5 to 2. If he wants to use a total of 140 cans, how many cans of green beans should he use? A. 38 cans B. 40 cans C. 22 cans D. 7 cans
Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0
This is a part:part ratio. to solve it we need to convert it into a part:whole ratio. we do this by adding the parts. the ratio of pumpkin cans to total cans is 5:7. 140/7=20. 20x5=100. 20x2=40. The answer is B. 40 cans.
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6 x (36÷12)2 + 8 = =
svp [43]

6*(36/12)2+8

=44

Hope this helped :T

7 0
3 years ago
Read 2 more answers
Christine performed the following experiment 20 times using a book that contains 462 pages.
wel

Using the probability concept, it is found that there is a 0.3 = 30% experimental probability that Christine will randomly choose a page that is divisible by 3.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In an experimental probability, these number of outcomes are taken from previous trials.

In this problem:

  • The experiment was made 20 times.
  • Of those, in 6 experiments(81, 105, 171, 159, 297, 387) she choose a page that was divisible by 3.

Then:

p = \frac{6}{20} = 0.3

0.3 = 30% experimental probability that Christine will randomly choose a page that is divisible by 3.

You can learn more about the probability concept at brainly.com/question/15536019

7 0
2 years ago
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
PLS HELPPPP MEEE <br> (explain ur answer)
adell [148]

Answer:

<em>(4). is the correct answer</em>

Step-by-step explanation:

(- 3, 1, 1)

(1). - 3 - 1 - 1 ≠ - 2  not an answer...

(2). - 3 - 1 + 3(1) ≠ 2 not an answer...

(3). 4( - 3) + 1 - 3(1) ≠ - 4 not an answer...

<em>(4). 2(- 3) + 3(1) + 4(1) = 1 </em>

<em>3(1) + 3(1) = 6 </em>

<em>- 3 = - 3(1) </em>

7 0
3 years ago
Expanded form of 680,705
denis23 [38]

\huge\boxed{600,000 + 80,000 + 700 + 5}

To find expanded form, we need to split up the digits. When you do that, you take one digit and cut off everything to the left of it, then make everything to the right zeros.

600,000 + 80,000 + 0 + 700 + 0 + 5

We don't need to keep the zeros.

\boxed{600,000 + 80,000 + 700 + 5}

We can check this by adding the numbers back up to get 680,705.

680,000 + 700 + 5

680,700 + 5

680,705

6 0
3 years ago
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