2 years ago

1/9(8 1/3(21x-51y)1x-108y+2x^2)

Mathematics

1 answer:

Ann [662]2 years ago

7 0

Answer:

569/ 9 x^2−153xy−12y

Step-by-step explanation:

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Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?

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Answer:

${(x + 6)}^{2} + {(y - 2)}^{2}=10$

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

${(x - a)}^{2} + {(y - b)}^{2} = {r}^{2}$

From the question, the center of the circle is located at (-6,2) and the radius is

$r = \sqrt{10}$

We substitute the center and radius to get:

${(x - - 6)}^{2} + {(y - 2)}^{2} = {( \sqrt{10} })^{2}$

Simplify to obtain:

${(x + 6)}^{2} + {(y - 2)}^{2}=10$

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