All categories

2 years ago

Sovle a triangle when A=40°, C=70°, and a=20.

Mathematics

1 answer:

Alex73 [517]2 years ago

7 0

Answer: B = 70°, b = 29.2; c = 29.2

Step-by-step explanation:

sum of angles in a triangle is 180

40+70 +X = 180

X is the last angle

110+x=180

x= 180-110 =70

A= 40°

B= 70°

C= 70°

the triangle is Isosceles triangle meaning two sides are equal , angle B = angle C

You might be interested in

What is the angle measurement of CBD?

WARRIOR [948]

Answer:

22°

Step-by-step explanation:

abd is a 90° angle so to find cbd you just have to do 90 minus 68 and you'll find 22°

6 0

2 years ago

Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25

tino4ka555 [31]

The answer is D. Here is the picture:

5 0

3 years ago

Read 2 more answers

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

Watch help video

adelina 88 [10]

Answer:

m= 6/-5

Step-by-step explanation:

m= y2-y1/x2-x1

m= 6-(-6)/-18-(-8)

m= 12/-10

m= 6/-5

8 0

2 years ago

Expand the binomial (2x+y^2)^5

ra1l [238]

Answer:

32x+y^10

Step-by-step explanation:

2^5 = 32

y^2*5 = y^10

6 0

3 years ago

Sovle a triangle when A=40°, C=70°, and a=20.​

Sovle a triangle when A=40°, C=70°, and a=20.