<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
The answer would be 5 hours and 50 minuets. It would be this because 2230 equals 10:30 count the hours between 1030 and 430 6 hrs then minus 10 min because the last hr isnt a full hour because it doesnt make it to 430.
12/16 which would reduce to 6/8 which can also reduce further to 3/4! :) so the final answer is 3/4.
Let x be the time she ran and y be the time she walked
then distance ran = 25x and distance walked = 5y
so 15x + 5y = 42
and x + y = 4
* second equn. by -5:-
-5x - 5y = -20
add this to the first equn:0
10x = 22
x = 2.2
distance she ran = 2.2 * 15 = 33 km
