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romanna [79]
3 years ago
15

Jasmine has 4 glass ornanents:green,orange,brown,and purple.How many ways can she hang them in a row so that the green and brown

ornaments are NOT next to each other.
Mathematics
2 answers:
Maksim231197 [3]3 years ago
8 0
1:green,purple, brown, orange
2:purple, green, orange brown
3:green, orange, brown purple
4:brown, orange, green, purple
tino4ka555 [31]3 years ago
4 0
The best way to solve this is by giving a visual idea of the glass ornaments. so We will have letter G represent Green, O for Orange, B for Brown, P for Purple.
Sample 1:G,O,B,P
Sample 2:G,P,O,B
Sample 3:P,G,O,B
Sample 4:O,G,P,B
Sample 5:G,O,P,B
This is what you can do this should be the right amount of ways to arrange them.

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On Thursday the high temperature was 0 °C. If it was three degrees colder on Friday, what was the temperature?
Rina8888 [55]

Answer:

-3 degrees C

Step-by-step explanation:

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8 0
2 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
NEED HELP ASAP!
vova2212 [387]

Answer:

2

Step-by-step explanation:

it's 2

8 0
3 years ago
Researchers investigated whether insomnia is related to education status. Adults living in a certain region were selected to par
Degger [83]

Answer:

A) 8 treatments

  1. Normal​ sleeper, high school dropout
  2. Normal​ sleeper, high school graduate
  3. .Normal​ sleeper, college graduate
  4. Chronic​ insomnia, college graduate
  5. Chronic​ insomnia, high school graduate
  6. Chronic​ insomnia, high school dropout
  7. Normal​ sleeper, some college
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B) 8 treatments

Step-by-step explanation:

<u>A) determine the number of treatments for this study </u>

The number of treatments for this study can be determined as : 2 * 4 = 8 treatments

and they are :

  1. Normal​ sleeper, high school dropout
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  4. Chronic​ insomnia, college graduate
  5. Chronic​ insomnia, high school graduate
  6. Chronic​ insomnia, high school dropout
  7. Normal​ sleeper, some college
  8. Chronic​ insomnia, some college

B) eight (8 ) treatments

7 0
2 years ago
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