Question

If 541 people use the swimming pool and children pay 1.75 dollars and adults pay 2.25 and in total earned was 1041.25 how many children were there

Answer 1

Answer:

352 children

Step-by-step explanation:

Solve algebraically using a system of equations

Assign variables

let "a" be the number of adults

let "c" be the number of children    <-- We want to find this

a + c = 541             Equation for number of people

2.25a + 1.75c = 1041.25           Equation for money

Rearrange the equation for people. Isolate the variable you don't want to find.

a = 541 - c

Substitute "541 - c", replacing "a", in the equation for money

2.25a + 1.75c = 1041.25              

2.25(541 - c) + 1.75c = 1041.25               Distribute over brackets

1217.25 - 2.25c + 1.75c = 1041.25               Collect like terms

1217.25 - 0.5c = 1041.25                   Simplified equation

Start isolating "c". Move anything that's not "c" to the right side. Move numbers in reverse BEDMAS order. That means we will add/subtract before dividng/multiplying. When moving a number, do its reverse operation to the entire equation.

1217.25 - 0.5c = 1041.25      Do the reverse of positive 1217.25

1217.25 - 1217.25 - 0.5c = 1041.25 - 1217.25    Subtract 1217.25 on both sides  

-0.5c = -176               Do the reverse of multiplying by -0.5

-0.5c/-0.5 = -176/-0.5               Divide both sides by -0.5

c = 352                Number of children

Therefore, there were 352 children in the pool.