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BARSIC [14]
3 years ago
9

Is (-1,4) a solution of the inequality y<2x+5

Mathematics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

No, (-1,4) is not a solution.

Step-by-step explanation:

This is actually a simple problem...don't overcomplicate it!

All you need to do is plug the values into the equation and solve!

y < 2x + 5

4 < 2(-1) + 5

4 < 3

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Does the graph represent a function?
S_A_V [24]
The answer is not it is not because if you use the vertical line test it does not pass and if you plotted the coordinates then x would repeat multiple times

Hope this helps

Have a great day/night
6 0
3 years ago
Read 2 more answers
Simplify (1 − cos x)(1 + cos x).<br><br> 1<br> cos2 x<br> sin2 x<br> tan2 x
Phoenix [80]
Answer

The expression is equivalent to sin^{2}x

The first step is to multiply the two expressions between parentheses :
(II)
There is a trigonometric identity that states :

Working with this expression :
⇒
(I)
Using the equation (I) in (II) :
⇒


Read more on Brainly.com - brainly.com/question/3907632#readmore
3 0
3 years ago
Help on both please ! Im a new student at this school and didn't learn this
larisa86 [58]
For the first one, you have to convert the fractions to an improper fraction. To do that you need to multiply the bottom denominator number (3) by the whole number (1) then you need to add the numinator, so 3x1+2= 5. You have to keep the denominator so 1 2/3 is equal to 5/3. Then do the same to 2 1/5, and you get 11/5. Now you have to find a common denominator, that's basically the smallest number that both numbers can go Into, the lowest common denominator for 3 and 5 is 15. So 3x5= 15, so we have to multiply the top number by 5 which is 25. So 5/3 is equal to 25/15, then 5x3= 15, so you need to multiply 11 by 3 which is 33. So 11/5 is equal to 33/15. Then you add them. Add the numinators (25+33=58. Then you keep the denominator 15. So when u add it it's 58/15 then you need to simplify that and you get 3 13/15.

The second one you turn them into improper fractions like I told you how to before (multiply the bottom number by the whole number then add he top number, then add he same denominator.) do that for both. Then you line them right next to each other and multiply across. (I just realized that they were the same number so they are equal to 5/3 and 11/5)
Then you do 5x11 and you get 55 then do 3x5 and you get 15. 55/15 is your answer, but you need to simplify it, you need to divide 55 by 15, (not all the way just the first number) so you do 15x3 and that's 45, then you subtract that from 55, and you get 10, so then you take your denominator (15) and you answer is 3 10/15. But when you simplify it it's 3 and 2/3


Hope I helped sorry it's so long and sorry for any typos it's so long I didn't go back and check
5 0
3 years ago
Select all that apply. Which of the following are proportions? 25/10=5/2,3/4=8/10,2/8=3/12,3/4=15/20
8_murik_8 [283]

Answer:

\frac{25}{10} = \frac{5}{2} is in proportion.

\frac{3}{4} = \frac{8}{10} is not in proportion.

\frac{2}{8} = \frac{3}{12} is in proportion.

\frac{3}{4} = \frac{15}{20} is in proportion.

Step-by-step explanation:

The first example is \frac{25}{10} = \frac{5}{2} and it is in proportion.

This is because, you will get the same simplest fraction (\frac{5}{2}) from the fraction \frac{25}{10} by dividing its numerator and denominator by 5.

The second example is \frac{3}{4} = \frac{8}{10} and it is not in proportion.

This is because, you can not  get the simplest fraction (\frac{3}{4}) from the fraction \frac{8}{10} after simplification.

The third example is \frac{2}{8} = \frac{3}{12} and it is in proportion.

This is because, you will get the same simplest fraction (\frac{1}{4}) from the fraction \frac{2}{8} by dividing its numerator and denominator by 2 and from the fraction \frac{3}{12} by dividing its numerator and denominator by 3.

The fourth example is \frac{3}{4} = \frac{15}{20} and it is in proportion.

This is because, you will get the same simplest fraction (\frac{3}{4}) from the fraction \frac{15}{20} by dividing its numerator and denominator by 5. (Answer)

3 0
3 years ago
Read 2 more answers
All of the following are true statements except _____.
shutvik [7]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

The false (wrong) equation among them is : A

\qquad \sf  \dashrightarrow \:  | - 93|  =  - 93

Because any number in a modulus comes out to be positive.

4 0
2 years ago
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