Answer:
<h3>I do not know what some of the words mean but I believe it is c</h3><h3 />
Step-by-step explanation:
Answer:
C. x³+10x²−5x+5
E. 7x⁵+4x²
F. x+8
Step-by-step explanation:
The graph they described should look something like the one i drew below.
So all you have to do is look at the number with the highest exponent.
If the exponent is an odd number and the x is positive then that function will have an end behavior like the picture i posted.
x³ is good
-x³ is bad because of the negative sign
x² is bad because exponent is even
x⁷ is good
123x¹ is good
P(x)=f(x)*g(x)
P(x)=(x-400)(1,200-2x)
P(x)=1,200x-2x^2-480,000+800x
P(x)=-2x^2+2,000x-480,000
Answer: Option <span>D. P(x) = -2x2 + 2,000x - 480,000</span>
-9/15y+3/21=5/15y-14/21
Move 5/15y to the other side. Sign changes from +5/15y to -5/15y
-9/15y-5/15y+3/21=5/15y-5/15y-14/21
-14/15y+3/21=-14/21
Move 3/21 to the other side. Sign changes from +3/21 to -3/21.
-14/15y+3/21-3/21=-14/21-3/21
-14/15y=-14/21-3/21
-14/21-3/21=-17/21
-14/15y=-17/21
Multiply both sides by -15/14
-14/15y(-15/14)
Cross out 15 and 15, divide by 15 then becomes 1
Cross out 14 and 14, divide by 14 then becomes 1
1*1*y=y
-17/21*-15/14
Cross out 15 and 21 , divide by 3. 15/3=2, 21/3=7
17/7*5/14=85/98
Answer: c. y=85/98
Answer:
10 Milk chocolates
8 dark chocolates
6 white chocolates
24 TOTAL
\frac{10}{24} Probability that Hanissa choose a milk chocolate
Now, since she has already eaten one chocolate, then what's left is 23 chocolates.
So, since the second one should be a white chocolate and there are 6 of them, then
\frac{6}{23} - probability of choosing a white chocolate.
Then, multiply,
( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}
Answer: 5/46 or 10.87%
Step-by-step explanation:
