First subtract 2 revolutions from the - 840 :- (- (840-720) = -120
This gives sin -120 which is in the 3rd quadrant of the unit circle
sin -120 = - sin 60 = - sqrt3/2
very positive about these results
The answer is Line 1 Only
this is the answer cause I just took the test
Answer:
K
Step-by-step explanation:
techincally, I don't know if I am right, but there is more than one answer. The boundries/restrictions of what length DF could be are 2.477 < x < 8.477
Answer:
3
Step-by-step explanation:
