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3 years ago

12.89503 rounded to the hundreths is

1 answer:

7 0

$\text{The hundredths place is the 2nd place after the decimal}\\\\\text{The number in the hundredths place in this case is 9}\\\\\text{You would round up if the number to the right of it it's 5 or greater}\\\\\text{You would keep it the same if the number to the right of it is 4 or less}\\\\\text{The number to the right of 9 is 5, so round up}\\\\\text{When you round, it would turn into: 12.90, since the 9 turns into a "10",}\\\text{then you carry the one over to the next number}\\\\$

$\boxed{\text{Answer: 12.90}}$

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Under a microscope, ms. kapinski studies a culture with bacteria. as the number of hours progresses, ms. kapinski sees that the

velikii [3]

Answer:

Study 1 Answers:

1) 0.76 represents the multiplier of the bacteria, in this case it is decreasing by 24% because the formula for exponential decay is 1 - r.

2) 1290 represents the initial value, or before the study began.

Study 2 Answers:

1) 1180 is the initial value, or before the study began.

2) Study 1 started with more bacteria

3) Study 1 is experiencing exponential decay, while study 2 is experiencing exponential growth

Step-by-step explanation:

Exponential functions are in the form $y=a(b)^x$ , where a is the initial value, b is the multiplier, and x represents inputs, such as hours after a bacteria study.

Any multiplier above 1.00 is experiencing exponential growth, meaning it grows gradually over time, and any multiplier below 1.00 is experiencing exponential decay, meaning it decreases in population over time.

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3 years ago

A local weather enthusiast wants to see if the last five summers have been warmer than normal for eloy, arizona. from the nation

motikmotik

For the local weather of Eloy, Arizona, the average for the last five years fits with the 30-year average.

<h3>What do you mean by standard deviation?</h3>

In statistics, Standard deviation is a measure of the variation of a set of values.

σ = standard deviation of a population

N = number of observations of population

X = mean

μ = population mean

The 30-year average for July was 90°. The standard deviation for this average is 2.1°. Thus, the temperature lies in the range around of 90° in July.

Therefore, the range of the temperature is,

t = 90 - 2.1 = 87.9

t = 90 + 2.1 = 92.1

The last five summers recorded have an average of 93. 5° and the value of a is 5%. Thus, the reduction is,

t = 92 - (92 x 2.5/100)

t = 89.70

This value of temperature lies in the range of 87.9-92.1 degrees Celsius. Hence, the two averages are probably the same.

Hence, for the local weather of Eloy, Arizona, the average for the last five years fits with the 30-year average. Option D is correct.

Learn more about the standard deviation here;

brainly.com/question/19243813

8 0

2 years ago

How would i solve for X? please explain.

kap26 [50]

In problems like this the outer and inner part are in equal ratio

4 0

3 years ago

Solve each equation by completing the square. If necessary, round to the nearest hundredth.

Ksenya-84 [330]

$1.)\\ \\ b^2+10b=75\\ \\ b^2+10b-75=0\\ \\\Delta = b^{2}-4ac = 10^{2}-4*1*(75)=100+300=400 \\ \\\sqrt{\Delta }=\sqrt{400}=20$

$b_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-10-20}{2}=\frac{-30}{2}=-15\\ \\b_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-10+20}{2}=\frac{10}{2}=5$

$2.)\\ \\ n^2-20n=-75\\ \\ n^2-20n+75=0\\ \\\Delta = b^{2}-4ac = (-20)^{2}-4*1*75=400-300=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$n_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{20-10}{2}=\frac{10}{2}=5\\ \\n_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{20+10}{2}=\frac{30}{2}=15$

$3.)\\ \\t^2+8t-9=0\\ \\\Delta = b^{2}-4ac = 8^{2}-4*1* (-9)=64+36=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$t_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-8-10}{2}=\frac{-18}{2}=-9\\ \\t_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{-8+10}{2}=\frac{2}{2}=1$

$4.)\\ \\m^2-2m-8=0\\ \\\Delta = b^{2}-4ac = (-2)^{2}-4*1* (-8)=4+32=36\\ \\\sqrt{\Delta }=\sqrt{36}=6$

$m_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{2-6}{2}=\frac{-4}{2}=-2\\ \\m_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{2+6}{2}=\frac{8}{2}=4$

$5.)\\ \\ v^2+4v-2=0\\ \\\Delta = b^{2}-4ac = 4^{2}-4*1* (-2)=16+8=24\\ \\\sqrt{\Delta }=\sqrt{24}= \sqrt{4*6}=2\sqrt{6}$

$v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-2\sqrt{6}}{2}=\frac{2(-2-\sqrt{6}}{2}= -2-\sqrt{6}\approx -2-2,45\approx -4,45\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{-4+2\sqrt{6}}{2}=\frac{2(\sqrt{6}-2}{2}= \sqrt{6}-2 \approx 2,45-2\approx 0,45$

3 0

3 years ago

Does anyone know the answer pleaseeee

pochemuha

Answer:

it b

Step-by-step explanation:

3 0

3 years ago

12.89503 rounded to the hundreths is​

12.89503 rounded to the hundreths is