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weqwewe [10]
3 years ago
11

Given diameters EB and FC, find the measure of arc EF. *

Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

Correct option: first one -> 45°

Step-by-step explanation:

FC is a diameter, so the arc FBC measures 180°.

If we have that FBC = FB + BC, then we can find the value of BC:

FB + BC = 180

135 + BC = 180

BC = 45°

If we call the center of the circle 'O, we have that the central angle EOF and the central angle BOC are vertically opposite angles, so EOF = BOC.

The central angles have the same measure that the arcs they are related, so we have that:

angle BOC = arc BC = 45°

angle BOC = angle EOF

angle EOF = arc EF = 45°

Correct option: first one

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Answer:

0, 1 , 2, 3, 4, 5, 6, 7, 8, 9, A, B, 10, 11, 12, 13, 14, 15, 16, 17, 18

Step-By-Step Explanation:

i will go from 0 to 20:

0: 0

1: 1

2: 2

3: 3

4: 4

5: 5

6: 6

7: 7

8: 8

9: 9

10: A (10 is another 'digit')

11: B

12: 10 (12 = 1*12^1 + 0* 12^0)

13: 11 (13 = 1*12^1 + 1*12^0)

14: 12 (14 = 1*12^1 + 2*12^0)

15: 13

16: 14

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18: 16

19: 17

20: 18

Just remember to use the notation A and B after the digit nine, for example

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23: 1B

24: 20

In other words, the answer is 0, 1 , 2, 3, 4, 5, 6, 7, 8, 9, A, B, 10, 11, 12, 13, 14, 15, 16, 17, 18

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