58 is 50 plus 8. So its 50 and 8.That is for the first one.
Find a common multiple in between the denominators.
10 and 3 and 5 -> the least common multiple is 30.
Change all the denominators to 30 by multiplying the top and bottom by the same number.
9/10=27/30
1/3=10/30
1/5=6/30
Subtract!
27/39-10/30-6/30=11/30
The answer is 11/30
Hope this helps!
Ie 32^2 - 4ac=0 so ac=256 and a+c=130
So, that means:2 equations ac=256 a+c=130 ie c=130-a
So,a(130-a)=256 so 130a -a^2=256 ie a^2-130a +256=0 (a-2)(a-128)=0
Finally,giving a= 2 or a=128 so, a=2 c=128 or a=128 c=2
Since, a>c , a=128 and c=2 ie (128,2)
Answer:
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Step-by-step explanation:
Answer:
y = 1/2x + 7
Step-by-step explanation:
Parallel lines have the same slope.
Therefore the new equation will have a slope(m) = 1/2
Substitute m = 1/2 and point (-2, 6) into y = mx + b to solve for "b"
y = mx + b
6 = 1/2(-2) + b
6 = -1 + b
7 = b
The new equation: y = mx + b
y = 1/2x + 7
