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den301095 [7]
3 years ago
13

150% of what number is 105

Mathematics
2 answers:
solmaris [256]3 years ago
7 0

Answer:

70

Step-by-step explanation:

To do this, we can set up an equation that models the situation.

1.5x=105

Now we divide both sides by 1.5 to find the original number.

x=70

artcher [175]3 years ago
3 0

Step-by-step explanation:

Hello there!

Divide 105 into 3 parts:

105/3=35

Multiply that by 2 to get 100% of x:

35 x 2 =70

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Write the square roots of 49 i in ascending order of the angle.
Troyanec [42]

Answer:

The square roots of 49·i in ascending order are;

1) -7·(cos(45°) + i·sin(45°))

2) 7·(cos(45°) + i·sin(45°))

Step-by-step explanation:

The square root of complex numbers 49·i is found as follows;

x + y·i = r·(cosθ + i·sinθ)

Where;

r = √(x² + y²)

θ = arctan(y/x)

Therefore;

49·i = 0 + 49·i

Therefore, we have;

r = √(0² + 49²) = 49

θ = arctan(49/0) → 90°

Therefore, we have;

49·i = 49·(cos(90°) + i·sin(90°)

By De Moivre's formula, we have;

r \cdot (cos(\theta) + i \cdot sin(\theta) )^{\dfrac{1}{2}}  =  \pm \sqrt{r} \cdot \left (cos\left (\dfrac{\theta}{2} \right ) + i \cdot sin\left (\dfrac{\theta}{2} \right ) \right )

Therefore;

√(49·i) = √(49·(cos(90°) + i·sin(90°)) = ± √49·(cos(90°/2) + i·sin(90°/2))

∴ √(49·i) = ± √49·(cos(90°/2) + i·sin(90°/2)) = ± 7·(cos(45°) + i·sin(45°))

√(49·i) = ± 7·(cos(45°) + i·sin(45°))

The square roots of 49·i in ascending order are;

√(49·i) = - 7·(cos(45°) + i·sin(45°))  and  7·(cos(45°) + i·sin(45°))

8 0
2 years ago
-3r + 7 - 3r - 12 in simplest form
Akimi4 [234]
Since the co-efficient or "r" is "-3" and "-3", it will simplify to "-6" as -3-3= -6.
then the two constant terms with are "7" and "-12" will simplify to "-5" as 7-12=-5. therefore, the simplest form is -6r -5

hope it helped!
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Answer:

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Step-by-step explanation:

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  A = Pe^(rt)

for P=2500 and r=0.12, this becomes ...

  A = 2500e^(0.12t)

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Answer:

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Step-by-step explanation:

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