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Serggg [28]
3 years ago
15

What's the answer to this problem?

Mathematics
2 answers:
marissa [1.9K]3 years ago
5 0
You insert the number that's on the x side into x and then you solve the equation to get y.
Olenka [21]3 years ago
3 0
Answers are y = 2 , y = 2.5
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A child building a tower with Blocks uses 15 for the bottom row. Each row has 2 fewer blocks than the previous row. What formula
xenn [34]

Answer:

B)blocks in 5th row=15+(5-1)(-2)

Step-by-step explanation:

We are given that

Number of block in bottom row=15

Each row has 2 fewer blocks than the previous row

We have to find the formula would you use to find the number of blocks in the 5th row.

Number of blocks in  second row=15-2=15+1(-2)

Number of blocks in third row=15-2-2=15+2(-2)

Number of blocks in 4th row=15-2-2-2=15+3(-2)

Number of blocks in 5th row=15-2-2-2-2=15+4(-2)

Therefore, number of block in 5th row

15+(5-1)(-2)

This is required formula to find the number of blocks in the 5th row

Hence, option B is true.

B)blocks in 5th row=15+(5-1)(-2)

4 0
3 years ago
Use Polynomials to Find Perimeter &amp; Area<br> Find the area of this rectangle.
Ostrovityanka [42]

Answer:

Area of rectangle =

l \times b

= 5x *( 5x -4)

=

{25x}^{2}  - 20x

Perimeter of rectangle = 2(l + b)

=2(5x +5x -4)

= 2(10x - 4)

= 20x - 8

8 0
3 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

  • |C| = \sqrt{a^2+b^2}

Then, the work consists in finding pairs (a,b) for which:

  • \sqrt{a^2+b^2}=3

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

I will use b =0.5, b = 1, b = 1.5, b = 2

b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i
4 0
3 years ago
Find the volume of each sphere to the nearest hundredth?​
Alenkinab [10]

Answer:

Can i have a diagram please

Step-by-step explanation:

4 0
3 years ago
Y=2x+3<br> solve for y<br> help me plz
ruslelena [56]

Answer:

this is already solved.

Step-by-step explanation:

the only thing left would be graphing it.

5 0
3 years ago
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