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ExtremeBDS [4]
3 years ago
9

Solve x2 – 8x + 15 < 0. Select the critical points for the inequality shown.

Mathematics
2 answers:
quester [9]3 years ago
4 0

Answer:

x=3,5

Explanation:

x2−8x+15=0

Try to express the terms of the equation in square form.

Adding 16 both sides of the equation,

(x2−2⋅x⋅4+42)+15=16

or,(x−4)2+15−16=0

or,(x−4)2−1=0

or,(x−4)2−12=0

This is the a2−b2=(a+b)(a−b)form.

(x−4+1)(x−4−1)=0

or,(x−3)(x−5)=0

Now, equate both the terms to zero since both of them when multiplied, give zero.

Either,

x−3=0

∴x=3

Or,

x−5=0

∴x=5

Ans:x=3,5 Hope this helpsXD...!!

olga_2 [115]3 years ago
3 0

Answer:

3<x<5

Step-by-step explanation:

an Univariate quadratic polynomial can be divided into the product of two first order equations

In this example, x2 - 8x + 15 =  (x-3) * (x-5) <0

as a result. the answer is 3< x <5

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The circumference of a pizza is about 38 inches. What is the diameter of the pizza? Round to the nearest tenth if necessary
anygoal [31]

Answer:

The diameter of the pizza is 12 inches

Step-by-step explanation:

Given:

Circumference of a pizza = 38 inches

To Find:

The Diameter of the pizza =?

Solution:

Circumference:

The distance around the edge of a circle (or any curvy shape). It is a type of perimeter.

We know that the shape of the pizza is circle.

So the given circumference is circumference of a circle.

Now,

Circumference of the circle(pizza)=2\pi r

where r is the radius of the circle

circumference of the pizza =38

Thus

2\pi r= 38

\pi r=\frac{38}{2}

\pi r=19

r=\frac{19}{3.14}

r=6.050 inches

Now,

Diameter = 2\times r

Diameter = 2\times 6.05

Diameter=12.1 inches

Rounding to the nearest tenth

Diameter=12 inches

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Write the subtraction fact 10-3 two ways
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10-3 or 10+(-3) that should help
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What is 5-2+(9÷1)×9+0
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I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb
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Expand each expression A ( x+1)^2 B(x-3)^2. C ( x+4)^2 D (x-1/2)^2
Elis [28]

The <em>expanded</em> expressions are shown below:

  1. (x + 1)² = x² + 2 · x + 1
  2. (x - 3)² = x² - 6 · x + 9
  3. (x + 4)² = x² + 8 · x + 16
  4. (x - 1/2)² = x² - x + 1/4
  5. 3 · (x - 5)² = 3 · (x² - 10 · x + 25) = 3 · x² - 30 · x + 75
  6. (1/2) · (x - 2)² = (1/2) · (x² - 4 · x + 4) = (1/2) · x² - 2 · x + 2

<h3>How to expand perfect square trinomials</h3>

<em>Perfect square</em> trinomials are polynomials of grade 2 with the form (a + b)² = a² + 2 · a · b + b². In this case, we have to expand six perfect square trinomials:

a) (x + 1)² = x² + 2 · x + 1

b) (x - 3)² = x² - 6 · x + 9

c) (x + 4)² = x² + 8 · x + 16

d) (x - 1/2)² = x² - x + 1/4

e) 3 · (x - 5)² = 3 · (x² - 10 · x + 25) = 3 · x² - 30 · x + 75

f) (1/2) · (x - 2)² = (1/2) · (x² - 4 · x + 4) = (1/2) · x² - 2 · x + 2

To learn more on perfect square trinomials: brainly.com/question/385286

#SPJ1

3 0
3 years ago
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