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ExtremeBDS [4]
2 years ago
9

Solve x2 – 8x + 15 < 0. Select the critical points for the inequality shown.

Mathematics
2 answers:
quester [9]2 years ago
4 0

Answer:

x=3,5

Explanation:

x2−8x+15=0

Try to express the terms of the equation in square form.

Adding 16 both sides of the equation,

(x2−2⋅x⋅4+42)+15=16

or,(x−4)2+15−16=0

or,(x−4)2−1=0

or,(x−4)2−12=0

This is the a2−b2=(a+b)(a−b)form.

(x−4+1)(x−4−1)=0

or,(x−3)(x−5)=0

Now, equate both the terms to zero since both of them when multiplied, give zero.

Either,

x−3=0

∴x=3

Or,

x−5=0

∴x=5

Ans:x=3,5 Hope this helpsXD...!!

olga_2 [115]2 years ago
3 0

Answer:

3<x<5

Step-by-step explanation:

an Univariate quadratic polynomial can be divided into the product of two first order equations

In this example, x2 - 8x + 15 =  (x-3) * (x-5) <0

as a result. the answer is 3< x <5

You might be interested in
Solve 2(4 x + 3) &lt; 5 x + 21. { x | x &lt; 9} { x | x &gt; -5} { x | x &gt; -9} { x | x &lt; 5}
Nesterboy [21]

Answer:

x <5

Step-by-step explanation:

2(4 x + 3) < 5 x + 21

Distribute

8x +6 < 5x +21

Subtract 5x from each side

8x -5x +6 < 5x-5x+21

3x +6 < 21

Subtract 6 from each side

3x+6-6 <21-6

3x <15

Divide each side by 3

3x/3 <15/3

x <5

5 0
3 years ago
If f(x)=2+abs(x-3) for all x, what's the value of the derivative f'(x) at x=3?
ruslelena [56]
No derivation at x=3 .
only at x=3
8 0
3 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
2 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!
ArbitrLikvidat [17]

Answer and Step-by-step explanation:

0 to the power of 4 is 0.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

7 0
2 years ago
Somebody help me.. please
jek_recluse [69]

Answer: B

just make the included side equal

5 0
3 years ago
Read 2 more answers
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