Answer:
If 
whenever 
f is <em>increasing</em> on I.
If 
whenever f is <em>decreasing</em> on I.
Step-by-step explanation:
These are definitions for real-valued functions f:I→R. To help you remember the definitions, you can interpret them in the following way:
When you choose any two numbers on I and compare their image under f, the following can happen.
- . Because x2 is bigger than x1, you can think of f also becoming bigger, that is, f is increasing. The bigger the number x2, the bigger f becomes.
- . The bigger the number x2, the smaller f becomes so f is "going down", that is, f is decreasing.
Note that this must hold for ALL choices of x1, x2. There exist many functions that are neither increasing nor decreasing, but usually some definition applies for continuous functions on a small enough interval I.
Because the coefficient of x^2 is -1, we know that a will be -1. Knowing that the coefficient of x is -4, we can calculate that p=2. Thus, we have -1(x+2)^2+q is our equation. This is equal to -x^2-4x-4+q. As the constant term must be 2, we can then see that q is 6.
As such, we have -1(x+2)^2+6=0 as our factorization.
To solve this equation, we can use the quadratic formula. Plugging in values, we have:
which is equal to: (when the fraction is simplified)
Answer : AB and DE are the secants
Explanation: Because they both intersect the circle in exactly 2 points
Answer:
A) x = 6
Step-by-step explanation:
4x - 2x + 6 = x + 12
Combine like terms
2x +6 = x+12
Subtract 6 from each side
2x+6-6 = x+12-6
2x = x+6
subtract x
2x-x = x+6-x
x = 6
