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3 years ago

What is the area of the squares with sides (2x-3)feet?

Mathematics

2 answers:

Damm [24]3 years ago

7 0

Answer:

$= 4 {x}^{2} - 12x + 9 {ft}^{2} \\$

Step-by-step explanation:

$area = {x}^{2} \\ = (2x - 3)^{2} \\ = (2x - 3)(2x - 3) \\ = 2x(2x - 3) - 3(2x - 3) \\ = 4 {x}^{2} - 6x - 6x + 9 \\ = 4 {x}^{2} - 12x + 9 {ft}^{2}$

hope this helps

brainliest appreciated

good luck! have a nice day!

LUCKY_DIMON [66]3 years ago

5 0

Answer:

4x^2 -12x +9 ft^2

Step-by-step explanation:

The area of a square is

A = s^2 where s is the side length

A = (2x-3) ^2

A = (2x-3) (2x-3)

FOIL

first 2x*2x =4x^2

outer 2x (-3) = -6x

inner -3*2x = -6x

last -3*-3 = 9

Add them together

4x^2 -6x-6x +9

Combine like terms

4x^2 -12x +9

The area is 4x^2 -12x +9 ft^2

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Step-by-step explanation:

Given sequence is:

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For that purpose, the common difference has to be found. Common difference, denoted by d, is the difference between consecutive terms of an arithmetic sequence

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