What is the area of the squares with sides (2x-3)feet?
2 answers:
Answer:

Step-by-step explanation:

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Answer:
4x^2 -12x +9 ft^2
Step-by-step explanation:
The area of a square is
A = s^2 where s is the side length
A = (2x-3) ^2
A = (2x-3) (2x-3)
FOIL
first 2x*2x =4x^2
outer 2x (-3) = -6x
inner -3*2x = -6x
last -3*-3 = 9
Add them together
4x^2 -6x-6x +9
Combine like terms
4x^2 -12x +9
The area is 4x^2 -12x +9 ft^2
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