What is the area of the squares with sides (2x-3)feet?
2 answers:
Answer:
Step-by-step explanation:
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Answer:
4x^2 -12x +9 ft^2
Step-by-step explanation:
The area of a square is
A = s^2 where s is the side length
A = (2x-3) ^2
A = (2x-3) (2x-3)
FOIL
first 2x*2x =4x^2
outer 2x (-3) = -6x
inner -3*2x = -6x
last -3*-3 = 9
Add them together
4x^2 -6x-6x +9
Combine like terms
4x^2 -12x +9
The area is 4x^2 -12x +9 ft^2
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Answer:
Would be the 3rd one I believe
Step-by-step explanation:
Use the formula i = p*r*t:
$456
$456 = $1600*r*6. Solving for r, r = ----------------- = 0.0475, or 4 3/4%
($1600)(6)
