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solniwko [45]
3 years ago
13

What is the area of the squares with sides (2x-3)feet?​

Mathematics
2 answers:
Damm [24]3 years ago
7 0

Answer:

= 4 {x}^{2}  - 12x + 9 {ft}^{2}  \\

Step-by-step explanation:

area =  {x}^{2}  \\  = (2x - 3)^{2}  \\  = (2x - 3)(2x - 3) \\  = 2x(2x - 3) - 3(2x - 3) \\  = 4 {x}^{2}  - 6x - 6x + 9 \\  = 4 {x}^{2}  - 12x + 9 {ft}^{2}

hope this helps

brainliest appreciated

good luck! have a nice day!

LUCKY_DIMON [66]3 years ago
5 0

Answer:

4x^2 -12x +9   ft^2

Step-by-step explanation:

The area of a square is

A = s^2 where s is the side length

A = (2x-3) ^2

A = (2x-3) (2x-3)

FOIL

first 2x*2x =4x^2

outer 2x (-3) = -6x

inner -3*2x = -6x

last -3*-3 = 9

Add them together

4x^2 -6x-6x +9

Combine like terms

4x^2 -12x +9

The area is 4x^2 -12x +9 ft^2

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Michael earns $900 per month, plus 5% commission on all his sales over $750. what is the minimum amount of sales Michael must ha
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<h3>The minimum amount of sales Michael must have to earn at least $2500 in a month is $ 32000</h3>

<em><u>Solution:</u></em>

<em><u>The expression to Michael earnings is:</u></em>

b + (c \times s)

Where,

b is the base salary, which is $ 900 in this sum

c is the commission rate

Given that commission rate is 5%

s is the sales

Michael must have to earn at least $2500 in a month

Here, at least means, "greater than or equal to" 2500

The inequality is framed as:

base salary + 5 % on sales \geq 2500

900 + \frac{5}{100} \times s \geq 2500\\\\\ 900 + 0.05s\geq 2500

Solve the inequality

0.05s\geq 2500-900\\\\0.05s \geq  1600\\\\Divide\ both\ sides\ by\ 0.05\\\\s\geq 32000

Thus, minimum amount of sales Michael must have to earn at least $2500 in a month is $ 32000

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What is y=-3x written in standard form
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5 0
3 years ago
9. Simran had some ₹2 and ₹ 5 coins.She exchanged them for ₹ 10 coins. If the number of ₹ 5 coins is one less than the number of
sertanlavr [38]

Answer:

Step-by-step explanation:

Let x be the number of 2 coins and y be the number of 5 coins. Let z be the number of 10 coins she exchanged. Then, we have the first equation

2x+5y = 10z

Since she has one 5 coin less than 2 coins, then y=x-1. So we get the equation

2x+5(x-1) = 10z

which is equivalent to

7x-5 = 10z

If we add 5 on both sides and factor out on the right by 5 we get

7x = 5(2z+1)

We can solve for x and get

x = \frac{5(2z+1)}{7}

Since x represents the number of 2 coins, we must have that x is an integer. That is, we cannot have, for example 1.5 2 coins. Since 7 doesn't divide 5, we must have that 7 divides 2z+1. That is, the value of z is such that the number 2z+1 is multiple of 7. That is 2z+1 = 7p where p is an integer.

If that is the case, then

x = 5p, then y = 5p-1. By having 2z+1 = 7p, we are forcing that p is an odd integer, so we have infinite solutions. For each value of p that is an odd integer, then x=5p and y=5p-1 is a solution to the problem

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What is the recursive rule for the sequence?
love history [14]

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8.6 - 7.2 = 1.4

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Recursive rule is a_n = a_{n-1} + d

a1 is the first term so a1= 4.4

d is the difference = 1.4

So recursive rule is

a_n = a_{n-1} + 1.4, where a1 = 4.4

4 0
3 years ago
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