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goldenfox [79]
3 years ago
10

The basketball court at Johnson Elementary School is the shape of a rectangle. It is 92 feet long and 46 feet wide. What is the

perimeter of the basketball court?
Mathematics
1 answer:
padilas [110]3 years ago
5 0

Answer:

The perimeter of the basketball court is <u>276 feet²</u>.

Step-by-step explanation:

Given:

The basketball court at Johnson Elementary School is the shape of a rectangle.

It is 92 feet long and 46 feet wide.

Now, to find the perimeter of the basketball court.

Length = 92 feet.

Width = 46 feet.

So, to get the perimeter we put formula:

Perimeter=2(length+width)

Perimeter=2(92+46)

Perimeter=2\times 138

Perimeter=276\ feet^2.

Therefore, the perimeter of the basketball court is 276 feet².

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You forgot to say how many miles she drove

Step-by-step explanation:

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What is the correct method of recording numerical information from an experiment?
olga55 [171]

Answer:

The correct method for recording numerical information from an experiment is the quantitative method.

Step-by-step explanation:

This method represents the way of recording that tracks variables (sometimes more than one) and how they interact with each other. This will help to establish relationship within your experiment.

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I NEED HELP PLEASE ASAP! :)
bonufazy [111]

Answer:

See below.

Step-by-step explanation:

Again, another great question!

This should be under physics, as it involves Work = Force * Distance. As Anne pushes the wheelbarrow with a force of 70 Newtons with respect to an angle of 50 degrees horizontal, the horizontal force is 70( cos 50 ). The distance over which the work is done is 25 meters, so work should be -

Work = ( 70( cos 50 ) )( 25 ),

Work = ( About ) 1124.87 Joules

<u><em>The work done when Anne pushes the wheelbarrow a distance of 25 meters, is 1124.87 Joules</em></u>

6 0
3 years ago
In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

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3 years ago
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Please help me in this questions....​
Ivahew [28]

Part (i)

I'm going to use the notation T(n) instead of T_n

To find the first term, we plug in n = 1

T(n) = 2 - 3n

T(1) = 2 - 3(1)

T(1) = -1

The first term is -1

Repeat for n = 2 to find the second term

T(n) = 2 - 3n

T(2) = 2 - 3(2)

T(2) = -4

The second term is -4

<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

T(n) = 2 - 3n

-61 = 2 - 3n

-61-2 = -3n

-63 = -3n

-3n = -63

n = -63/(-3)

n = 21

Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer:  21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

T(2n) = 2 - 6n

Now subtract T(2n) from T(n)

T(n) - T(2n) = (2-3n) - (2-6n)

T(n) - T(2n) = 2-3n - 2+6n

T(n) - T(2n) = 3n

Then set this equal to 24 and solve for n

T(n) - T(2n) = 24

3n = 24

n = 24/3

n = 8

This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.

<h3>Answer: 8</h3>
4 0
3 years ago
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