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andrew-mc [135]
3 years ago
11

If t8 = 4 and t12 = −2, find the first three terms of the arithmetic sequence.

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

  14.5, 13, 11.5

Step-by-step explanation:

The general term (an) of an arithmetic sequence with first term a1 and common difference d is ...

  an = a1 + d(n-1)

Then the 8th term is ...

  a8 = a1 + d(8-1)

and the 12th term is ...

  a12 = a1 + d(12-1)

So, the difference between these terms is ...

  a12 -a8 = (a1 +11d) -(a1 +7d) = 4d

  = (-2-4) = -6 . . . . . substituting values for a12 and a8

Then the common difference is

... d = -6/4 = -3/2

Using this, we can find a1 from a8.

  4 = a1 +7·(-3/2) = a1 - 10.5

  14.5 = a1 . . . . . . . add 10.5 to both sides of the equation

This is the first term. The second is this value with the common difference added:

  14.5 + (-1.5) = 13

The third term is this with the common difference added:

  13 + (-1.5) = 11.5

In summary, the first three terms are ...

  14.5, 13, 11.5

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