All categories

2 years ago

Please help! Will give brainliest, pls no fake answers or links. :)

2 answers:

7 0

6 x 6 =
The cube has 6 sides and each side is 6 inches so it’s 6 x 6 = 36 inches
10 feet = 120 inches + 30 inches = 150 inches
No she won’t have enough for all 6 boxes

inessss [21]2 years ago

3 0

Answer:

A. NO PHOTO AVAILABLE

B. No.

C. 72 ft (6 inches left over)

Step-by-step explanation:

a: N/A

b: 24 x 6 = 144 inches on each side

1 ft = 12 in

144 in = 12 ft

Stephanie only had enough wrapping paper to wrap only 1 gift box, with 6 inches left over. 1 foot and 6 inches will not be enough to cover all the gift boxes.

c: Multiply and then add remainder to get a subtraction problem. Then, subtract the remainder of 6 from the number from the product of the multiplication:

144 x 6 = 864 + 6 = 870

870 - 6 = 864 inches, or 72 feet in lowest terms, would be enough to cover all the gift boxes, with 6 inches left over.

I hope this helps! Have a good night ;)

Yep, it's 8:00 P.M. in my town, and 2:00 A.M. in P.A.

Please mark this as brainliest! i would really appreciate it!

You might be interested in

Nolan wrote 1.63 as a fraction in simplest

Naya [18.7K]

Answer:

Step-by-step explanation:

First, I wrote the fraction as 1 63/100. I believe this is simplest form so the numerator is 63.

4 0

2 years ago

Researchers ask a random sample of 1,001 adults nationwide whether they favor or oppose the legalization of marijuana. Fifty-fiv

natima [27]

Answer:

b. It will decrease by a factor of 2

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The lower end of the interval is given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}}$

The upper end of the interval is given by:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}}$

The length of the interval is the subtraction of the upper end by the lower end, so it is:

$L = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

This means that the length is inverse proportional to the square root of the size of the sample.

So, if the sample size is multiplied by 4, the length of the interval is going to decrease by a factor of 2.

4 0

2 years ago

HELP write in slope intercept form through (6,-1) parallel to 3x-y=2

Murrr4er [49]

Answer:

3x-y=2

m1=-3/-1

m1=3

Since parallel, m1=m2 so,

m1=m2=3

The slope of straight line passing through the point (6,-1) is

y-(-1)=m2(x-6)

y+1=3(x-6)

Step-by-step explanation:

I don't say you have to mark my ans as brainliest but friend if it has helped you,plz don't forget to thank me....

3 0

3 years ago

In the diagram, polygon ABCD is flipped over a line of reflection to make a polygon with vertices at A′, B′, C′, and D′. Points

DIA [1.3K]

if point A( 2,2) is reflected across the line Y then the new position A' is (-2,2) and the distance AY = distance A'Y if A is reflected across line R it is now at point B and the distance AR = distance BR lets say the point A(2,2) was perpendicular to the line R at the point (1, 4) then when reflected the point A now at location B will have coordinateswhen flipped over a line of reflection the lengths are still the same the point to the line of reflection is the same length as the line of reflection to the reflected position the distance from the original point to the reflected point is twice the distance from the original point to the line of reflection cannot see your polygon. here is an example

7 0

2 years ago

Segments AB , CD , and EF intersect at point O, points A, E, C and points B, F, D are collinear so that AO ≅ OB , CO ≅ OD . Prov

katovenus [111]

If points A, E and C are colinear, then they lie on the same line. The same statement you can say about points B, F and D.

1. Consider triangles AOC and BOD. In these triangles:

AO≅OB (given);
CO≅OD (given);
∠AOC≅∠BOD (as vertical angles).

Thus, ΔAOC≅ΔBOD by SAS Postulate (If any two corresponding sides and their included angle are the same in both triangles, then the triangles are congruent). Corresponding parts of congruent triangles are congruent, then

AC≅BD;
∠ACO≅∠BDO;
∠CAO≅∠DBO.

Since angles ACO and BDO are alternate interior angles between lines AE and BF with transversal CD and these angles are congruent, then lines AE and BF are parallel.

This gives you that

∠CEO≅∠OFD;
∠ECO≅∠ODF.

2. Consider triangles ECO and FDO. In these triangles

∠CEO≅∠OFD (previous proof);
CO≅OD (given);
∠ECO≅∠ODF (previous proof).

Therefore, ΔECO≅ΔFDO by AAS Postulate (if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent). Then CE≅FD.

3. Note that

AE=AC+CE;
BF=BD+DF.

Since AC≅BD and CE≅DF, then AE=AC+CE=BD+DF=BF.

7 0

3 years ago