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Wewaii [24]
2 years ago
12

ind the length of the longest side of the rectangle whose vertices are given. A(2, 1), B(5, 4), C(0, 3), D(3, 6) 2 rad2 3 rad2 r

ad26
Mathematics
1 answer:
trasher [3.6K]2 years ago
5 0

Distance between A and B  

= Distance between C and D  

= sqrt((4 - 1)^2 + (5 - 2)^2)  

= sqrt(3^2 + 3^2)  

= sqrt(2 * 3^2)  

= sqrt(3^2) * sqrt(2)  

= 3sqrt(2)  

Distance between B and C  

= Distance between A and D  

= sqrt((4 - 3)^2 + (5 - 0)^2)  

= sqrt(1^2 + 5^2)  

= sqrt(26)  

Since sqrt(26) is more than 3sqrt(2), the length must be sqrt(26).

Hope this helps you.

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Solution -9-8(1+4h)= -17
geniusboy [140]
Step 1. <span>Add </span>9<span> to both sides

</span>-8(1+4h)=-17+9

Step 2. Simplify -17+9 to -8

-8(1+4h)=-8

Step 3. Divide both sides by -8

1+4h=1

Step 4. Cancel 1 on both sides

4h=0
 Step 5. Divide both sides by 4

h=0

Done! :) Hope this helps! :)

To check -9-8(1+4h)=-17 follow these steps below:

Step 1. Let h = 0

-9-8*(1+4*0)=-17

Step 2. Simplify 4 * 0 to 0

-9-8*(1+0)=-17

Step 3. Simplify 1 + 0 to 1

-9-8*1=-17
<span>
Step 4. </span><span>Simplify  8 * 1 to 8
</span>
-9-8=-17
<span>
Step 5. </span><span>Simplify -9 -8 to -17
</span><span>
</span>-17=-17
<span>
Done! :)
 </span>
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