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3 years ago

Please help if you can

Mathematics

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

x=4 or x=-5/7

Step-by-step explanation:

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Standardized Test Practice

Ulleksa [173]

Answer:

8x+6y=48

x+y=7

multiply bottom equation by 6:

8x+6y=48

6x+6y=42

subtract equations:

2x=6

divide 6 by 2:

x=3

therefore:

y=4

6 0

3 years ago

Read 2 more answers

What is the measure of 0 in radians?

Allushta [10]

Answer:

Thus, the expression to find the measure of θ in radians is θ = π÷3

Step-by-step explanation:

Given that the radius of the circle is 3 units.

The arc length is π.

The central angle is θ.

We need to determine the expression to find the measure of θ in radians.

Expression to find the measure of θ in radians:

The expression can be determined using the formula,

where S is the arc length, r is the radius and θ is the central angle in radians.

Substituting S = π and r = 3, we get;

Dividing both sides of the equation by 3, we get;

3 0

3 years ago

An explanation for 168 divided by 5.6

Nataly_w [17]

168 divided by 5.6 equals 30 hope this helps

3 0

3 years ago

Help my semester ends in 17 hours

Nata [24]

Find the lengths of the sides. Determine how long a right triangle side lengths are.

4 0

2 years ago

Estimate the area of Alberta in square miles. Show your reasoning

ella [17]

Answer: About $278,250\ mi^2$

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid can be calcualted with the formula:

$A_t=\frac{h}{2}(B+b)$

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

$A_r=lw$

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

$A=\frac{h}{2}(B+b)+lw$

Substituting vallues, you get:

$A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2$

Therefore, the area of of Alberta is about $278,250\ mi^2$ .

5 0

3 years ago