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Blababa [14]
3 years ago
14

The probability of a spinner landing on a 6 is 2/7 . What is the probability that the spinner will land on a number other than 6

?
A.2/7
B.1/7
C.6/7
D.5/7
Mathematics
2 answers:
Anton [14]3 years ago
5 0
This is really simple.  We know that landing a 6 is a 2/7 chance that means there is a 5/7 chance of NOT landing a 6 which means that the probability of landing a number that is not 6 would be 5/7.  Your answer is D.) 5/7
charle [14.2K]3 years ago
5 0
D.5/7 I mean,it's pretty simple. If the probability of landing 6 is 2/7
2-7=5.
5/7
It's simple once worked out.

ANS: D.5/7
Hope this helps!
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Y=-x-3
nadya68 [22]

Answer: Heyaa! :)

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<em>Slope:  </em>−1

<em>y-intercept: </em>(0,−3)

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<em>Slope:</em> 4

<em>y-intercept: </em>(0,−5)

  • <em>3. 2x-y=-2 =</em> 2

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  • <em>4. x+y=4 =</em> 1

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<em>y-intercept:</em> (0,4)

  • <em>5. 3x+4y=-12 = - 3/4</em>

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(0,−3)

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4 0
2 years ago
To which graph does the point (−1, 3) belong? y ≥ 2x + 6 y ≥ 3x − 1 y ≥ −x + 3 y ≥ −2x + 5
Anna35 [415]
Well first find the slope of the point
y=mx+b  y=-1x+3
slope = -1
then put the problem in point slope form y - y1 = m (x-x1)
y + 3 = -1 (x+1) then solve for y=mx+b again
so y> 2x + 6 is the answer
4 0
3 years ago
Read 2 more answers
Please Help ASAP!!!!!!
Bumek [7]

Answer: 6

The sides are equal.

Thus

3x-6=x+2\\2x=8\\x=4

$JP=x+2=4+2=\boxed{6}$

4 0
3 years ago
Read 2 more answers
A restaurant sells about 330 sandwiches each day at a price of $6 each $.25 decrease in price. 15 more sandwiches are sold per d
zmey [24]

Answer:

restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

Step-by-step explanation:

to calculate current revenue= $6 x 330 = $1980

suppose x as the number of times the price to be dropped by $0.25

then find new price.. i.e

new price= $(6-0.25x)

and, new sell=330 +15x sandwiches

therefore, the new revenue would be= (6-0.25x)(330 +15x)

in order to maximize the current revenue, simplify the above equation and make it complete square using x

(6-0.25x)(330 +15x)

=1980-82.5x +90x -3.75x^{2}

=1980 + 7.5x -3.75x^{2}

=1980-3.75 (-2x+x^{2}) ----> taking out common

now, to make a complete square lets add and subtract 1 inside the parentheses

=1980-3.75(-1+1-2x+x^{2})

=1980 +3.75 -3.75(x^{2} -2x +1)

=1983.75 -3.75 (x-1)^{2}---->(1)

as (x-1)^{2} is positive always, minimize the other term in order to maximize the total revenue.

so the minimum possible value of (x-1)^{2} = 0

therefore, x=1

putting x in eq(1) the revenure becomes,

$(1983.75-0)=> $1983.75

therefore, restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

3 0
3 years ago
Select all the correct answers.
ValentinkaMS [17]

Answer:

ideas and conflict and maybe elements depending on the story

3 0
3 years ago
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