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jasenka [17]
3 years ago
7

-16b+32 can somebody help me factor this polynomial?

Mathematics
1 answer:
barxatty [35]3 years ago
8 0
-16b+32
=-16(b-2)
Cheers,Irys
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If perimeter rectangular is 204 feet the width 45 feet what’s the length of the yard
Minchanka [31]
The length of the yard is 159 ft.
5 0
3 years ago
Read 2 more answers
Need math help asap please! :/ thanks
Dominik [7]

The rule to remember about generating the perpendicular family to a line is we swap the coefficients on and x and y, remembering to negate one of them. Then the constant is set directly from the intersecting point.


So we have


y = 3x + 2


-3x + 1y = 2


Swapping and negating gets the perpendiculars; the constant is as yet undetermined.


1x + 3y = constant


Since we want to go through (0,2), we could have just written


x + 3y = 0 + 3(2) = 6


3y = -x + 6


y = (-1/3) x + 2


Third choice


5 0
2 years ago
Given: The coordinates of rhombus WXYZ are W(0, 4b), X(2a, 0), YO, -4b), and Z(-2a, 0).
Shkiper50 [21]

Answer:

∴ MNOP is Rectangle

midpoint of XY (N) : (a , - 2b)

Step-by-step explanation:

W (0 , 4b)   X ( 2a , 0)   Y (0 , -4b)   Z (-2a , 0)

M (midpoint of WX) : ( (0 + 2a)/2 , (4b + 0)/2)  i. e. (a , 2b)

N (midpoint of XY) : ( (2a + 0)/2 , (0 - 4b)/2)  i. e. (a , - 2b)

O (midpoint of YZ) : ( (0 - 2a)/2 , (- 4b + 0)/2)  i. e. (- a , - 2b)

P (midpoint of ZW) : ( (0 - 2a)/2 , (4b + 0)/2)  i. e. (- a , 2b)

MN: length = 2b + 2b = 4b     MN segment perpendicular to x axis (slope undefined)

NO: length = a + a = 2a     NO segment parallel to x axis (slope = 0)

OP: length = 2b + 2b = 4b     OP segment perpendicular to x axis (slope undefined)

PM: length = a + a = 2a     NO segment parallel to x axis (slope = 0)

MN = OP and MN // OP and MN ⊥ PM

NO = PM and NO // PM and NO ⊥ OP

∴ MNOP is Rectangle

midpoint of XY (N) : (a , - 2b)

please draw graph to prove

8 0
2 years ago
Solve for C.<br> Thank you to whoever answers!!!!!!!!!!!!!!!!!!!
faltersainse [42]

Answer:

c=7

Step-by-step explanation:

How to solve your problem

8=−3+29

8=−3c+298=-3c+298=−3c+29

Solve

1

Subtract

29

292929

from both sides of the equation

8=−3+29

8=−3c+298=-3c+298=−3c+29

8−29=−3+29−29

8−29=−3c+29−298{\color{#c92786}{-29}}=-3c+29{\color{#c92786}{-29}}8−29=−3c+29−29

2

Simplify

3

Divide both sides of the equation by the same term

4

Simplify

Solution

=7

Hope this helps!

Have a great day!

-Lea

5 0
2 years ago
Read 2 more answers
(b)
ElenaW [278]

Answer:

Step-by-step explanation:

a) r = √(1² + (-5²)) = √26 = 5.09901...

   θ = tan⁻¹(-5/1) = 4.9097... radians

   (5.1, 4.9)

b) r = - 5.09901...

   θ = 4.9097... - π = 1.76819...

   (-5.1, 1.8)

7 0
3 years ago
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