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Greeley [361]
3 years ago
13

A zookeeper predicted that the weight of a newborn lion would be 2.8 pounds.

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

There is 20% error in zookeeper's calculations.

Step-by-step explanation:

Given,

Approx weight of newborn lion = Approx value =2.8 pounds

Exact weight of newborn lion = Exact value = 3.5 pounds

Percent error = \frac{|approx-exact|}{exact}*100

Percent error = \frac{|2.8-3.5|}{3.5}*100\\

Percent error = \frac{|-0.7|}{3.5}*100

Percent error = \frac{70}{3.5}

Percent error = 20%

There is 20% error in zookeeper's calculations.

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Use the grouping method to factor x3 + x2 + 5x + 5.
lisov135 [29]

Answer:

answer is a

Step-by-step explanation:

look at picture

3 0
3 years ago
- 7h + 2(-4h +5) > -4h +1 +10. Solve for h​
navik [9.2K]

Hello.

-7h + 2(-4h + 5) > -4h + 1 + 10 ; solve for h

Our first step is to get rid of all the parenthesis. We can do this by simplifying everything out.

-7h - 8h + 10 > -4h + 11

Add like terms.

-15h + 10 > -4h + 11

Now, we must isolate our variables. We do this by moving all variables to one side and moving our other numbers to the other.

Subtract 10 from both sides. Then, add 4h to both sides.

-15h + 4h > 11 - 10

Simplify.

-h > 1

Divide both sides by -1.

However, keep in mind that when dividing with a negative, you must change the sign. Therefore, > turns into <

-h ÷ -1 < 1 ÷ -1

h < -1

6 0
3 years ago
A bee flies 25 m north of the hive then 10 m east 5 m west and 10 m south. How far north and east of the hive is it now? Explain
mafiozo [28]

Answer:

20 meters north.

Step-by-step explanation:

(I did it on a paper not to lose track.) First we go 25 north. Then ten east. Five south. And 10 west again. So in East/West we didn't move but we moved 5 down/south so we are still at twenty. If you don't understand still draw it on a paper.

5 0
3 years ago
What is 2x+3=-7 for property of equality
Tasya [4]

Answer:

-5

Step-by-step explanation:

2x+3=-7

2x=-7-3

2x=-10

x=-10/2

x=-5

3 0
3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

4 0
3 years ago
Read 2 more answers
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