Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Because if you multiply 2 different irrational numbers (like the following)
You will get an irrational answer.
BUT
if you multiply the same square root (which are both irrational, you get a rational number)
Answer:20
Step-by-step explanation:
My best guess is a line graph because it shows the consistent numbers and then you can lay them all out after you have completed the graph
The factors for given equation f(x)=
.
- (x-1) - No
- (x-3) - No
- (x+3) - Yes
- (x-5) - Yes
- (x+5) - Yes
<u>Step-by-step explanation:</u>
The given equation is f(x)= .
Add 0 at the end of the equation.
= 0.
Let us group the given equation,
=0.
⇒ Group 1: 
.
Group 2: 
.
Pull out factor from each group,
⇒ Group 1: 
.
Group 2: (x+3) (-25).
Join the two group since both (x+3) is common in both groups.
=0.
One of the factor is (x+3).
Other factors are solved by the formula, 
.
= (x+5) (x-5) .
The other factors are (x+5) and (x-5).
