The arc length is
where <em>C</em> is the given curve and d<em>s</em> is the line element. <em>C</em> is defined on 0 ≤ <em>t</em> ≤ 3π by the vector function,
so the line element is
So we have
Hey there!
If these hexagons are congruent, then each angle is congruent to the one that is in the same position as it is. In this case, I and V are congruent because they are both last. K and U are congruent because they are both second to last.
While looking over the answer options, you should be able to see that Angle J and Angle S is the only answer with angles that match up, because they are both the first angle in the set.
I hope this helps!
8:32 simplyfies to 1:4 .....there is your answer 1:4
Step-by-step explanation:
Distance Chase thought he travelled = 40 feet
The actual distance travelled by him = 32 feet
Error % = (40 - 32)/ 100
= 8/100
= 0.08
The vertex is always halfway between the focus and the directrix, and the parabola always curves away from the directrix, so I'll do a quick graph showing the focus, the directrix, and a rough idea of where the parabola.
<span>So the vertex, exactly between the focus and directrix, must be at <span>(h, k) = (1,
–2)</span><span>. The absolute value of </span>p<span> is the distance between the vertex and the focus and the distance between the vertex and the directrix. (The sign on </span>p<span>tells me which way the parabola faces.) Since the focus and directrix are two units apart, then this distance has to be one unit, so </span><span>| p | = 1</span>.<span>Since the focus is to the left of the vertex and directrix, then the parabola faces left (as I'd shown in my picture) and I get a negative value for </span>p<span>: </span><span>p = –1</span><span>. Since this is a "sideway" parabola, then the </span>y<span> part gets squared, rather than the </span>x<span> part. So the conics form of the equation must be:</span>(y<span> – (–2))2 = 4(–1)(x – 1)</span><span>, or </span><span>(y<span> + 2)</span>2<span> = –4(</span>x<span> – 1)</span></span>
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</span></span><span><span>Please give me brainiest! I'm striving for the next rank</span></span> </span>