30 is 5.47 as a square root, and between integers 6 and 7.
W=4
I hope this helps! Any questions?
<u>w</u><u>=</u><u>-</u><u>1</u><u>.</u><u>5</u>
<u>w</u><u>=</u><u>2</u>
Answer:
Solution given:
again
keep square root alone
solve subtraction of 7-2
Squaring on both side
2w²-19w+31=5²-2*5*2w+4w²
take terms one side
2w²-19w+31-25+20w-4w²=0
-2w²+w+6=0
2w²-w-6=0
doing middle term factorisation
2w²-(4-3)w-6=0
2w²-4w+3w-6=0
take common from each two term
2w(w-2)+3(w-2)=0
(w-2)(2w+3)=0
either
w=2
or
W=-3/2=-1.5
I might be wrong but wouldn't it be ab/360 (pi r^2) - 1/2 bh?
I am not positive.
1) The graph
The corresponding graph shows a growing curve, its shape is kind of the right half of a parabola that opens upward and starts at the point (0, 2500).
The vertical axis corresponds to C(j), it contains divisions of 2500 units, and are marked 2500, 5000, 7500, 10000, 12500, 15000 and 17500.
The horizontal axis corresponds to j, and the marks are 75, 150, 225, 300, 375, and 450.
2) Domain
Domain is the set of possible values for the independent variable, which is placed on the horizontal axis. This is the possible values of j.
They are all the positive numbers and zero, the the domain is:
All real numbers, j, such that j ≥ 0
3) Range
Range is the set of possible images (dependent variable); this is the possible values of C(j).
As you can see on the graph C(j) ≥ 2500
Then, the range is [2500, ∞).
