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3 years ago

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Mariana paid $6 for 5 pound of apples. How much will she pay for 3 pounds of apples? Let x be the amount she will pay for 3 lbs.

Please write an equation! The answer is 3.6.

1 answer:

mestny [16]3 years ago

5 0

$x =(6 \div 5) \times 3$
I believe that's the answer... hope I helped!

You might be interested in

Which of the following expression is equivalent to 35+14

Korvikt [17]

Answer:

49

Step-by-step explanation:

I would add the tens place and ones place together. The tens place; is 30+10 (From the 3 and 1 in the tens place) and 5+4, which is 40+9, which is 49.

5 0

3 years ago

You $5,000 in a simple interest bearing account. If the annual interest rate is 3.5% , what will your account balance be in 10 y

Natalija [7]

Answer:

Therefore my account balance will be in 10 year=$6,750

Step-by-step explanation:

Simple interest: Simple interest is calculated on the same principal each year.

$I=\frac{Prt}{100}$

I= simple interest.

r = rate of interest per annum.

t= time

Compound interest: The principal is not same each year. The principal will change from the second year.

The principal of 2nd year = Principal+ interest of 1st year.

The principal of 3rd year = Principal of 2nd year+ interest of 2nd year.

and so on

The Amount $(A)=P(1+\frac{r}{100})^t$

Here P= $5,000

r=3.5%

and t=10 years

$I=\$\frac{5000\times 3.5\times 10}{100}$

=$1750

Therefore my account balance will be in 10 year=$(5,000+1750)=$6,750.

8 0

4 years ago

Help with number 6 please. thank you.

Gwar [14]

Answer:

See Below.

Step-by-step explanation:

We are given that:

$\displaystyle \frac{dT}{dt} = -k(T - T_0)$

And we want to show that:

$\displaystyle T = T_0+Ae^{-kt}$

From the original equation, divide both sides by (<em>T</em> - <em>T₀</em>) and multiply both sides by dt. Hence:

$\displaystyle \frac{dT}{T-T_0}= -k\, dt$

Take the integral of both sides:

$\displaystyle \int \frac{dT}{T- T_0} = \int -k \, dt$

Integrate. For the left integral, we can use u-substitution. Note that <em>T₀</em> is simply a constant. Hence:

$\displaystyle \ln\left|T - T_0\right| = -kt+C$

Raise both sides to e:

$\displaystyle e^{\ln\left|T-T_0\right|} = e^{-kt+C}$

Simplify:

$\displaystyle \begin{aligned} \left| T- T_0\right| &= e^{-kt} \cdot e^C \\ \\ &= e^C\left(e^{-kt}\right) \\ \\ &=Ae^{-kt} & \text{Let $e^C = A$}\end{aligned}$

Since the temperature <em>T</em> will always be greater than or equal to the surrounding medium <em>T₀</em>, we can remove the absolute value. Hence:

<em /> $\left(T - T_0\right) = Ae^{-kt}$ <em />

Therefore:

$\displaystyle T = T_0+Ae^{-kt}$

5 0

3 years ago

Read 2 more answers

75% of what number is 15? make it so clear pls pls

mojhsa [17]

<u>2</u><u>0</u> is the answer.

Step-by-step explanation:

Take a look at the given question,

"75% of <em><u>what number</u></em> is 15"

Let's substitute this "<em>what </em><em>number"</em><em> </em>as "x"

$75$ % $\times x = 15$

$→x = \frac{15}{75 \: percent}$

$→x = \frac{15}{ \frac{75}{100} }$

$→x = \frac{15}{0.75}$

To make the denominator as positive for making calculations more easy, we get,

$x = \frac{15 \times 100}{0.75 \times 100}$

$→x = \frac{1500}{75}$

Now after doing the division, we get,

$x = 20$

Hence, 75% of <u>2</u><u>0</u> is 15.

5 0

3 years ago

Perform the indicated operation. 6/11 - 4/11. 1/11 2/11 10/11

Scilla [17]

6/11 -4/11 = 2/11

Choice C

7 0

3 years ago