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Zigmanuir [339]
3 years ago
13

The graph of y = square root of 9 - x end square root - 5 is shown below. What are the x-intercept and the y-intercept, and for

what values of x is the function defined?
answers:
x-Intercept: (−16, 0), y-intercept: (0, −2), x ≥ 9
x-Intercept: (−16, 0), y-intercept: (0, −2), x ≤ 9
x-Intercept: (−16, 0), y-intercept: (0, −2), x ≥ −5
x-Intercept: (0, −2), y-intercept: (−16, 0), x ≥ −2

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0

Answer:

x-intercept: (-16,0), y-intercept: (0,-2), x ≤ 9

Step-by-step explanation:

See the graph in the attachment.

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The percent of change = ((new value - old value) / old value) × 100%

Our new value = $261.50

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Plug our values into the equation above.

(($261.50 - $382) / $382) × 100% = -31.54%

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The functions and g are defined as follows.
elena-s [515]

Answer:

- 27 and 7

Step-by-step explanation:

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f(- 6) = 4(- 6) - 3 = - 24 - 3 = - 27

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Quinn had $4.00 he spent 1/2 of his money on baseball cards,1/4 of it on a drink and 1/8 of it on bubble gum. how much does quin
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He has $.50 left
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3 years ago
Find the area of a plane figure bounded by lines
natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6   ⇒   x² + x - 2 = 0   ⇒   (x + 2)(x - 1) = 0   ⇒   x = -2, x = 1

Now, integrate from x = -2 to x = 1

\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,    <em>the bottom of the integral is -2 </em>

= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

= \int\limits^1_2 {-x^{2}-x+2 } \,  

= \frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,

= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

= \frac{-9}{3} + \frac{3}{2} +6

= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
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