I'm not 100% sure, but I'm pretty sure it's 1/12, 1/12, 1/12, 1/12
Answer:
k=20
Step-by-step explanation:
when x approaches 4, the denominator x-4 approaches 0
if the denominator is 0, it means that this is invalid
if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit
so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4
so x^2 + x - k = 0 when x = 4
4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20
The given expression is
And since we have x+2 common in numerator and denominator, there is a hole at x+2=0, that is at x=-2
And a function is undefined when denominator is zero. And at x=-6, denominator become zero.
So, at x=-6, the function is undefined, or there is a vertical asymptote at x=-6 and hole at x=-2 .
Answer:
x=3
Step-by-step explanation:
firstly this equation isn't possible without it equaling to something. I set it equal to zero and got x=3.
EX:
(x-3)^(3)=0
