All categories

2 years ago

10 points please show work too

Mathematics

1 answer:

Dima020 [189]2 years ago

5 0

I think the answer is *1,008* I hope I get it right

You might be interested in

I have 1hundreds, 9tens, 9 o es, 8 rentas. What Number am I ?

Digiron [165]

You are 199. 8 that is your number

7 0

2 years ago

You sell tickets for admission to your school play and collect a total of $104. Admission prices are $6 for adults and $4 for st

riadik2000 [5.3K]

Answer:

11 tickets

Step-by-step explanation:

1. write an equation:

First, variable x symbolizes the number of adults who bought tickets. And variable y symbolizes the number of students.

If each adult paid $6, and each student paid $4, and the total dollars you've collected is 104, this is how we'll write our equation:

6x + 4y = 104

2. we can write another equation based on this information: "You sold 21 tickets". Which concludes that the number of tickets adults and students had paid for equals the number of tickets you've sold:

x + y = 21

3. now, we've got two equations. Let's compensate:

x + y = 21

x = 21 - y

6x + 4y = 104

6 (21 - y) + 4y = 104

126 - 6y + 4y = 104

-6y + 4y = -22

-2y = -22

y = -22 / -2

So the number of student tickets is <u>11</u>.

3 0

2 years ago

A faucet is used to add water to a large bottle that already contained some water. After it has been filling for 5 seconds, the

enot [183]

Answer:

Step-by-step explanation:

Has to much pressure

4 0

2 years ago

We intend to estimate the average break time of Dunder Mifflin employees. From a previous study, we believe that the average tim

arsen [322]

Answer:

The minimum sample size that we should consider is of 60 employees.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

We want our 99 percent confidence interval to have a margin of error of no more than plus or minus 2 minutes. What is the smallest sample size that we should consider?

We need to find n for which $M = 2, \sigma = 6$