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2 years ago

Write an equation, in slope-intercept form(y = mx + b) that models the total cost of the rental over time.

Mathematics

2 answers:

OlgaM077 [116]2 years ago

7 0

It should be y= 25x + 50

kompoz [17]2 years ago

4 0

Y = 50/2 + 50

i think it’s the answer because rise over run it’s rises 50 and goes right by 2 and the 50 is the b where it started.

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3 years ago

Can you help me find a formula to solve this problem?

olasank [31]

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3 years ago

Read 2 more answers

Inferential statistical tests are used for all of the following except: a. describing a sample with means and standard deviation

Anika [276]

Answer:

a. Describing a sample with mean and standard deviation.

Step-by-step explanation:

Statistics can be categorized into descriptive and inferential statistics.

descriptive statistics uses data for descriptions through numerical analysis. It can be further divided in four parts.

Measures of Central Tendency ( Mean, Median, and Mode)

Measures of Frequency (Count, Percent, Frequency)

Measures of Position (Percentile Ranks, Quartile Ranks.)

Measures of Dispersion ( Range, Standard Deviation)

Inferential statistics however is based on assumptions and conclusions and generalizations drawn from samples or checks.

options b to d are all examples of inferential statistics while option a is an example of descriptive statistics.

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3 years ago

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3 years ago

The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes

Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(completing the exam in one hour or less)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 60) =0.023= 2.3\%$

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

$P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%$