In the given graph point B is a relative maximum with the coordinates (0, 2).
The given function is
.
In the given graph, we need to find which point is a relative maximum.
<h3>What are relative maxima?</h3>
The function's graph makes it simple to spot relative maxima. It is the pivotal point in the function's graph. Relative maxima are locations where the function's graph shifts from increasing to decreasing. A point called Relative Maximum is higher than the points to its left and to its right.
In the graph, the maximum point is (0, 2).
Therefore, in the given graph point B is a relative maximum with the coordinates (0, 2).
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Answer:
It is given that ABCD is a parallelogram, so AB || DC by the difinition of parallelogram. So, <1 = <2 by the alternate interior angles theorem. It is also given that DC bisects <BDE, so <2 = <em><u><</u><u>3</u><u> </u></em> by the <em><u>d</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>o</u><u>f</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>b</u><u>i</u><u>s</u><u>e</u><u>c</u><u>t</u><u>o</u><u>r</u><u>.</u></em> Therefore,<em> <u><</u><u>1</u></em><u> </u> = <3 by the <em><u>t</u><u>r</u><u>a</u><u>n</u><u>s</u><u>i</u><u>t</u><u>i</u><u>v</u><u>e</u><u> </u><u>p</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>o</u><u>n</u><u>g</u><u>r</u><u>u</u><u>e</u><u>n</u><u>c</u><u>e</u><u>.</u></em>
Part A.
We could take, for example:

For x ≥ -3 we have vertical line (x-intercept = -3) and shaded region on the right side of the line.
For y ≥ 3 we have horizontal line (y-intercept = 3) and shaded region above that line.
Part B.
Simply, substitute x and y coordinates of D and E <span>to the system of inequalities from part A, and check if its is true, what we get.
</span>

so point D is a solution,

and point E is also a solution to <span>our system of inequalities.
</span>
Part C.
There are two ways we could do that. First is the same as in part B. We substitute x and y coordinates of each school and check if inequality is true or false:


So Timothy can attend schools C and F.
We can also draw a graph of that inequality (pic 2).
Answer:
Step-by-step explanation:
if you use a graphing calculator you we see that the smaller the leading coeffient the wider the parabola.
or use a table and plug in values for y for each x
y = x² 5x² 15x²
x = 1 1 5 15
x = 2 4 20 60
y is larger for a larger ax² a coeffient
so the is more narrow for a higher coeffient
f(x) = 5x² has the smallest coeffient so the widest parabola