To get the maximum height, we first determine the time at which this maximum height is attained by differentiating the given equation and equating the differential to zero.
h(t) = -0.2t² + 2t
Differentiating,
dh(t) = -(0.2)(2)t + 2 = 0
The value of t is equal to 5. Substituting this time to the original equation,
h(t) = -0.2(5²) + 2(5) = 5 ft
Thus, the maximum height is 5 ft and since it will take 5 seconds for it to reach the maximum height, the total time for it to reach the ground is 10 seconds.
Answers: maximum height = 5 ft
time it will reach the ground = 10 s
Step-by-step explanation:
Geometric Sequence formula for general term:
an = a1(r^n-1)
a1 = 4 × (-5)^1-1
a1 = 4
r = -5
Summation formula for geometric sequence :
Sn = a1 ( 1 - r^n / 1 - r )
...<em>take n from the top of the summation.</em>
= 4 ( 1 -(-5)^6 / 1 -(-5)
= -10416.
Answer:
9
Step-by-step explanation:
9 times 4 is 36 and 9 times 1 is 9
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Answer:
72°
Step-by-step explanation:
180-3x=2x
5x=180
x=36
Angle CBE = 2(36) = 72
Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
