Question

During an experiment, 321.1 grams of strontium phosphite are measured into a beaker. How many moles of strontium phosphite are in the beaker?

Answer 1

321.1 g of strontium phosphite will contain 0.76 moles of strontium phosphite in the beaker.

Explanation:

It is known that 1 mole of any substance is equal to the molar mass of that substance. So for the case of strontium phosphite, the molar mass is found to be 420.8 g/mol.

This means 1 mole of Strontium phosphite will contain 420.8 g of strontium phosphite.

Then 1 g of strontium phosphite will have $\frac{1}{420.8}$ moles of strontium phosphite.

So, 321.1 g of strontium phosphite will contain $\frac{321.1}{420.8}=0.76 moles$

Thus, 321.1 g of strontium phosphite will contain 0.76 moles of strontium phosphite in the beaker.